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babymother [125]
3 years ago
9

Explain how rays AB and AC form both a line and an angle.

Mathematics
2 answers:
konstantin123 [22]3 years ago
5 0

Answer:

An angle is defined as two rays with a common endpoint, so CAB (or BAC) is an angle. A line is described as an infinite set of points that extend forever in either direction, which these rays also do.

Step-by-step explanation:

GuDViN [60]3 years ago
4 0

A straight line (180o) is still an angle. Would you be wondering if the question said "Can 179o be a real angle?" No you would simply draw it. 1 degree more and you have 180o and it is an angle as well.

So you have a line that is both a line and an angle with A in the middle.

You might be interested in
How do you solve (Arc)QPT if <QZT = 120
yuradex [85]
By definition, the arc length is given by:
 arc = R * theta * ((2 * pi) / 360)
 Where,
 theta: angle in degrees
 R: radio
 We have then:
 (Arc) QPT if <QZT = 120:
 theta = 360-120 = 240 degrees
 R = 13.5 units
 Substituting values we have:
 (Arc) QPT = R * theta * ((2 * pi) / 360)
 (Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
 (Arc) QPT = 56.55 units
 Answer:
 
(Arc) QPT = 56.55 units
7 0
3 years ago
What is the x-intercept for the equation -2x + 5y = -10
Zielflug [23.3K]

Answer:

The x-intercept is at the point (5,0).

Step-by-step explanation:

-2x + 5y = -10

At the x intercept y = 0 so we substitute y = 0 into the given equation:

-2x + 5(0) = -10

-2x = -10

x = 5.



5 0
3 years ago
Read 2 more answers
Simplify the expression ​
finlep [7]

Answer:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}

Step-by-step explanation:

We have the expression:

\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x}

The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x

We will get:

(\frac{2}{2} )\frac{2*x - 2}{2*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x}

Now we can directly add the terms to get:

\frac{4*x - 4}{4*x}  - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x}  = \frac{x - 6}{4*x}

We can't simplify this anymore

3 0
3 years ago
James and Michael are the partners in a local business. They needed $480,000 to start the
larisa [96]

Answer:

James invested $160,000

Step-by-step explanation:

- In total, they needed $480,000 to start the business

- 1:2 ratio means one of them payed double the amount than the other

so the expression would be,

2x + x = 480,000

Let x represent how much they each need to invest

the expression can be simplified to,

3x = 480,000

now you need to get x alone, this would be done be dividing both sides by 3

\frac{3x}{3} = \frac{480,000}{3}\\x = 160,000

James invest $160,000

Michael invest $160,000 x 2 = $320,000

and if you add them together, you get the total amount

$320,000 + $160,000 = $480,000

Let me know if you have any questions !

7 0
2 years ago
Read 2 more answers
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
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