The functional groups determine the shapes of macromolecules and this in turn determines their functions
The correct answer is D. They have two successive sets of teeth including milk teeth and permanent adult teeth
Explanation:
In biology, a diphyodont is an animal that has two different sets of teeth, this often means the animal has a set of baby teeth that are later replaced by permanent teeth, this occurs in most mammals including humans. Additionally, diphyodont differ from other types of animals that have either only one set of teeth (monophyodonts), for example, toothed whales or change their teeth permanently (polyphyodont), for example, crocodiles. Thus, mammals are diphyodont because "they have two successive sets of teeth including milk teeth and permanent adult teeth".
The possibility for all of the mentioned birds to live all in a same area is because they are all specialized and occupy a certain niche in the food chain, thus not standing in each others ways when it comes to competition for food.
All of these birds have adapted to be able to survive in their respective environment, developing characteristics that will enable them to be superior in something. Through natural selection, the individuals that were performing better, got the chance to mate, thus the offspring was better adapted and stronger in its niche of the food chain.
The robins and the blue jays are birds that are very opportunistic in their food choice, thus giving them greater flexibility and ability to survive, they mostly feed on worms, insects, fruits, vegetables, so they have a big menu.
The finches are specialized in eating nuts and seeds, thus avoiding the competition with the previous two, thus having that food type for themselves.
The owls and hawks are both birds of pray, but the owls hunt mostly at night, while the eagles during the day. Also, the owls prefer to have rodents as their pray, while the hawks are mostly eating other birds, thus not standing in each other's ways.
Answer:
In Labrador dogs, black coat is dominant to chocolate, normal vision is dominant to progressive retinal atrophy (PRA), and normal hip joint is dominant to hip dysplasia. All these genes assort independently. Two dogs that are heterozygous for alleles of all three genes are crossed. Using rules of probability (not a Punnett square), what is the chance that the first pup born to these dogs will be chocolate, have normal vision, and have normal hip joints?
BbVvHh x BbVvHh= BBVVHH, BbVvHh, BbVvHh, bbvvhh
Bb= black coat dominant
Vv= Normal vision dominant
Hh= Normal hip join dominant
probability of having a first born of these dogs will be chocolate, have normal vision and have normal hip joint is 0
Explanation:
As the punette square gives 3:1 phenotype having three black coat, normal vision and normal hip joint and one chocolate, progressive retina altropy and hip dysplasia
They contain genetic information and assist in making proteins
