Answer:
<h3>A) 204m</h3><h3>B) 188m</h3>
Step-by-step explanation:
Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60
The velocity of the rocket at its maximum height is zero
v = dh/dt = -32t + 96t
At the maximum height, v = 0
0 = -32t + 96t
32t = 96
t = 96/32
t = 3secs
Substitute t = 3 into the modeled function to get the maximum height
h(3) = -16(3)^2 + 96(3) + 60
h(3) = -16(9)+ 288 + 60
h(3) = -144+ 288 + 60
h(3) = 144 + 60
h(3) = 204
Hence the maximum height reached by the rocket is 204m
Get the height after 2 secs
h(t) = -16t^2 + 96t + 60
when t = 2
h(2) = -16(2)^2 + 96(2) + 60
h(2) = -64+ 192+ 60
h(2) = -4 + 192
h(2) = 188m
Hence the height of the rocket after 2 secs is 188m
A = 21/2 i will write something too just to fill up the space
Answer:
62.5
Step-by-step explanation:
Data provided in the question:
Actual demand = 59
Previous forecast = 64
Alpha = 0.3
Now,
The forecast for the next period be using simple exponential smoothing will be given as
= [ Alpha × Actual demand ] + [ (1 - Alpha) × Previous forecast ]
= 0.3 × 59 + [ ( 1 - 0.3 ) × 64 ]
= 17.7 + 44.8
= 62.5
Answer:
Step-by-step explanation:
180/4 is 45 so you could say the farmer plants 135 Acers of corn and only 45 of wheat
3x+y=180
Hope this helped.
Answer:
true
Step-by-step explanation:
just my opinion but for me it's true
