1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
12345 [234]
3 years ago
12

Im Giving Brainliest............. Someone Plzz Help?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

Answer:

For the first one 25.925%

The second is 23.333%

The third is 27.27%

Let me know if this helps!

You might be interested in
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
Solve for x: 2x + 8 = 4x - 10
IgorLugansk [536]

Answer:

18=2x

x=9

Step-by-step explanation:

hope it helps bro

6 0
2 years ago
Read 2 more answers
What's the markdown price of this red dress
il63 [147K]
It was marked down $18.49.
3 0
3 years ago
PLZZ HELLP ME !!!! WILL GIVE BRANLIEST !!!!
Zielflug [23.3K]

Answer:

24mm

Step-by-step explanation:

since it's a similar triangle, we solve;

EH/EG=DH/DG

EH=56mm;

EG=44.8mm;

DH=35mm;

DG=X+4.

Fix them,

56/44.8=35/x+4

cross multiply

56(x+4)=35×44.8

56x+224=1,568

collect the like term

56x=1,344

divide via by 56

56x/56=1344/56

x=24mm

Check/ verify

EH/EG=DH/DG

56/44.8=35/24+4

56/44.8=35/28

CROSS MULTIPLY OVER THE EQUAL SIGN.

56×28=35×44.8

1,568=1,568

THAT'S CORRECT.

6 0
3 years ago
Serial numbers for a product are to be made using 2 letters followed by 3 numbers. If the letters are to be taken from the first
Daniel [21]
2 Letters chosen among 6 with no repeat:
a) the first has 6 ways
    the second has 5  ways

Then to choose 2 letters among 6, with no repeat, there are 6x5 = 30 ways

 b) 3 numbers are taken from the digits 0 through 9 with repeats (total = 10)
     the first has 10 ways
     the second has 10  ways
    the third has 10  ways

Then to choose 3 numbers among 10, with repeat, there are 10x10x10= 1000 ways
And the total serial numbers that can be generated is
30 x 1000 = 3000
8 0
3 years ago
Other questions:
  • Which biconditional statement below is true?
    13·1 answer
  • Write the function that represents the following question: What do you get when you take away 23 from k? f(k) =
    11·1 answer
  • Solve for N <br> 2/7 = 10/N
    8·1 answer
  • Classify the following triangle as acute, obtuse, or right
    8·1 answer
  • Molly shared a spool of ribbon with 12 people. Each person received 3 feet of ribbon. Which equation can she use to find r, the
    8·2 answers
  • 5/7 = x/70 solve the proportion
    7·2 answers
  • Pls heeeeeeeeeeeeeeeeeeeeeeeeelp
    13·1 answer
  • What are the coordinates of A? b) What are the coordinates of B?​
    10·1 answer
  • 69 predicted the pandemic????
    9·2 answers
  • Which function is the inverse of f(x) = -5x- 4?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!