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3 years ago

Which postulate proves these triangles are similar? (giving brainliest and thanks to all!)

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

It’s SAS. Hope I helped sorry if I got it wrong

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Which expression is equivalent to -1/12x-1/3?

hichkok12 [17]

B. If you multiply 1/12 by (-x) it's -1/12x and if you multiply 1/12 by (-4) it's -4/12 which is equivalent to -1/3.

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3 years ago

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PLEASE HELP MEEE

STALIN [3.7K]

If there are 16 ounces in a pound, and 8 ounces costs $8, The best answer would be D. $16 per pound

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4 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

5 0

3 years ago

J= -8c^2 - 4cd - d^2 k= -3c^2 +7cd - 3d^2 j+k =

irina [24]

J=-8c²-4cd-d²
k=-3c²+7cd-3d²
j+k=
-8c²-4cd-d²-3c²+7cd-3d²
-11c²-4d²+3cd

6 0

4 years ago

What’s 15x - 25 + 2 = 22 (with steps)

cupoosta [38]

Answer: x= 3

Step-by-step explanation:

15x-25+2=22

15x-25=25

15x=50

x=3.333333

x=3

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3 years ago

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