Answer:
Yes
6(x+0.4) is equivalent to 3(2x+0.8)
Step-by-step explanation:
Given in the questions two expressions
6(x + 0.4)
3(2x + 0.8)
We will apply distributive law
It is a law relating the operations of multiplication and addition, stated symbolically
<h3>a(b + c) = ab + ac</h3><h3 />
6(x + 0.4)
= 6(x) + 6(0.4)
= 6x + 2.4
3(2x + 0.8)
= 3(2x) + 3(0.8)
= 6x + 2.4
Since both equations when expanded have same answers, hence they are equivalent
<span>Data
set X and data set Y both have the same interquartile range. If the
first quartile of data set X is less than the first quartile of data set
Y, then the third quartile of data set X is greater than the third
quartile of data set Y.
False</span>
<h3>yes<em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>simplify </u></em><em><u>it</u></em><em><u> </u></em><em><u>right</u></em></h3>
To solve this, first subtract 3kx from both sides so that both the x variables are on the same side. This will result in: 24=9kx-3kx.
Since 9kx and -3kx are like terms, they will combine and you will get 24=6kx
Now, divide 6k from both sides to isolate x and you get x=24/6k.
However, you notice that 24 and 6k both have a common factor which is 6, so you simplify 24/6k to 4/k which gives you your answer of x=4/k
