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harina [27]
3 years ago
14

Rock debris from space called enter Earth and are called . If they survive this fall and land on Earth, they are called .

Chemistry
2 answers:
Serjik [45]3 years ago
8 0
Meteorites, I think it’s an asteroid when in space and a meteorite once it lands
Step2247 [10]3 years ago
6 0

Answer:

meteoroids, meteors, meteorites

Explanation:

yea

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The excessive demand of energy leads to......​
dem82 [27]

Answer:

industrial activity

Explanation:

3 0
3 years ago
Scientific Notation - PLEASE HELP!
zmey [24]

Answer:

0.0931 is the ans i think

8 0
4 years ago
You are to give ampicillin, with a recommended dose of 25 mg/kgmg/kg , to a child with a mass of 24 kgkg . If stock on hand is 2
Anastasy [175]

Answer:

2.4 capsules

Explanation:

You are to give ampicillin, with a recommended dose of 25 mg/kg (25 mg of ampicillin per kg of body weight), to a child with a mass of 24 kg. The mass of ampicillin to be given is:

24 kg body mass × (25 mg ampicillin/ 1 kg body mass) = 600 mg ampicillin

The stock on hand is 250 mg/capsule (250 mg ampicillin per capsule). The number of capsules required to supply 600 mg of ampicillin is:

600 mg ampicillin × (1 capsule/250 mg) = 2.4 capsule

4 0
3 years ago
An inherited characteristic of an organism is called a ___________________.
Firlakuza [10]

Answer:

fitness. the ability of an organism to survive and reproduce in its environment. adaptation. the inherited characteristic that increases an organism's chance of survival.

5 0
3 years ago
Read 2 more answers
For water ∆H°vap = 40.7 kJ/mol at 100.°C, its boiling point. Calculate ∆S° for the vaporization of 1.00 mol water at 100.°C and
damaskus [11]

Answer : The value of change in entropy for vaporization of water is 1.09\times 10^2J/mol

Explanation :

Formula used :

\Delta S^o=\frac{\Delta H^o_{vap}}{T_b}

where,

\Delta S^o = change in entropy  of vaporization = ?

\Delta H^o_{vap} = change in enthalpy of vaporization = 40.7 kJ/mol

T_b = boiling point temperature of water = 100^oC=273+100=373K

Now put all the given values in the above formula, we get:

\Delta S^o=\frac{\Delta H^o_{vap}}{T_b}

\Delta S^o=\frac{40.7kJ/mol}{373K}

\Delta S^o=1.09\times 10^2J/mol

Therefore, the value of change in entropy for vaporization of water is 1.09\times 10^2J/mol

5 0
3 years ago
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