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galben [10]
3 years ago
12

How many moles are in 153’pp grams of KClO3

Chemistry
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

n = 1.24 moles

Explanation:

Given that,

Mass = 153 grams

Molar mass of KClO₃ = 122.55 g/mol

We need to find the number of moles.

We know that,

No. of moles = given mass/molar mass

So,

n=\dfrac{153}{122.55 }\\\\n=1.24

So, there are 1.24 moles in 153 g of KClO₃.

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Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

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Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

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\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

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Write the following in scientific notation. Include the unit or it will be marked wrong. a. 3450 meters b. 0.0000432 liters c. 5
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A saturated solution of potassium chlorate is dissolved in 100g of water. If the saturated solution is cooled from 90 degrees Ce
dedylja [7]

Mass would crystallize out : 24 g

<h3>Further explanation </h3>

Solubility is the maximum amount of a substance that can dissolve in some solvents. Factors that affect solubility

  • 1. Temperature:
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We can use solubility graph to solve this.

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3 years ago
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