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galben [10]
3 years ago
12

How many moles are in 153’pp grams of KClO3

Chemistry
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

n = 1.24 moles

Explanation:

Given that,

Mass = 153 grams

Molar mass of KClO₃ = 122.55 g/mol

We need to find the number of moles.

We know that,

No. of moles = given mass/molar mass

So,

n=\dfrac{153}{122.55 }\\\\n=1.24

So, there are 1.24 moles in 153 g of KClO₃.

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How many mL of a 0.193 M aqueous solution of ammonium bromide, , must be taken to obtain 8.42 grams of the salt?
PilotLPTM [1.2K]

Answer:

445 mL NH₄Br

Explanation:

(Step 1)

Convert grams ammonium bromide (NH₄Br) to moles using its molar mass.

Molar Mass (NH₄Br): 14.007 g/mol + 4(1.008 g/mol) + 79.904 g/mol

Molar Mass (NH₄Br): 97.943 g/mol

8.42 grams NH₄Br                1 mole
-----------------------------  x  ------------------------  =  0.0860 moles NH₄Br
                                         97.943 grams

(Step 2)

Calculate the volume of NH₄Br using the molarity equation. Then, convert liters (L) to milliliters (mL).

Molarity (M) = moles / volume (L)

0.193 M = 0.0860 moles / volume

(0.193 M) x volume = 0.0860 moles

volume = 0.445 L

1,000 mL = 1 L

0.445 L NH₄Br           1,000 mL
------------------------  x  ------------------  =  445 mL NH₄Br
                                        1 L

8 0
2 years ago
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