Answer:
Option C. 0.73 g/cm³
Explanation:
From the question given above, the following data were obtained:
Mass = 80 g
Area (A) = 10000 cm²
Thickness = 0.11 mm
Density =?
Next, we shall convert 0.11 mm to cm. This can be obtained as follow:
10 mm = 1 cm
Therefore,
0.11 mm = 0.11 mm × 1 cm / 10 mm
0.11 mm = 0.011 cm
Thus, 0.11 mm is equivalent to 0.011 cm.
Next, we shall determine the volume of the paper. This can be obtained as follow:
Area (A) = 10000 cm²
Thickness = 0.011 cm
Volume =?
Volume = Area × Thickness
Volume = 10000 × 0.011
Volume = 110 cm³
Finally, we shall determine the density of the paper. This can be obtained as follow:
Mass = 80 g
Volume = 110 cm³
Density =?
Density = mass / volume
Density = 80 / 110
Density = 0.73 g/cm³
Therefore the density of the paper is 0.73 g/cm³
According to Newton's Second Law of Motion, the force is directly proportional to mass and acceleration. However, mass and acceleration are inversely proportional to each other. It is best interpreted by the equation: F = ma. So, for the same amount of force, it would produce less acceleration on the greater mass of the helicopter.
Answer:
Graph C
Explanation:
This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.
The new electrostatic force will be 384 units.
The electrostatic force of attraction between two charges (charge of object 1) and (charge of object 2) separated by a distance d is given by
is the permittivity of free space.
Initially, we have,
Now, if the charge of object 1 is multiplied by 1, the charge of object 2 is multiplied by 3, and the distance separating objects 1 and 2 is divided by 4, we have, .
The new electrostatic force will be,
units.
We have,
Hence,
Hence, the new electrostatic force will be 384 units.
To read a similar problem on electrostatic forces visithttps://brainly.com/question/16049250
<h2>
Answer:</h2>
3.0cm
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Explanation:</h2>
For lenses in an achromatic combination, the following condition holds, assuming the two lenses are of the same materials;
d = ---------(i)
Where;
d= distance between lenses
f₁ = focal length of the first lens
f₂ = focal length of the second lens
From the question;
f₁ = 4.5cm
f₂ = 1.5cm
Substitute these values into equation (i) as follows;
d =
d =
d = 3.0cm
Therefore, the distance between the two lenses is 3.0cm