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svp [43]
3 years ago
10

A daredevil on a motorcyclo attempts to clear a 420-meter-wide river from a 210-meter-high cliff. What must his initial horizont

al velocity
be?
Physics
1 answer:
timama [110]3 years ago
5 0

Answer:

<em>His initial velocity (speed) must be 64.16 m/s.</em>

Explanation:

<u>Horizontal Motion</u>

When an object is horizontally launched at a speed v from a height h, the maximum horizontal distance (also called <em>Range</em>) traveled by the object can be calculated as follows:

\displaystyle d=v\cdot\sqrt{\frac  {2h}{g}}

Our daredevil is attempting to clear a river d=420 m wide with his motorcycle from a cliff h=210 m high. We need to find the speed needed to safely reach the opposite edge of the river.

From the above equation, we solve for v:

Speed:

\displaystyle v=d\cdot\sqrt{\frac  {g}{2h}}

\displaystyle v=420\cdot\sqrt{\frac  {9.8}{2\cdot 210}}

\displaystyle v=420\cdot\sqrt{\frac  {9.8}{420}}

v = 64.16 m/s

His initial velocity (speed) must be 64.16 m/s.

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Anyone know the answer to this, would kindly appreciate it
Ipatiy [6.2K]

Answer:

The found value of r is:

r = 94.7

Explanation:

We know that

cosθ = Base / Hypotenuse

θ is the always the angle between base and hypotenuse

In this right angles triangle, the angle θ is given 63°.

Which means that the Base is 43 and the hypotenuse is r

Base = 43

Hypotenuse = r

Substitute θ=63°, Base = 43 and hypotenuse = r in the formula of cosθ mentioned above:

cos 63° = 43/r

Rearrange

r = 43/cos63°

r = 43/0.454

r= 94.7

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Answer:

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Explanation:

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• 3 laps of 200 meter track = 600 meters
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