All categories

3 years ago

If anybody can help me pls do

Mathematics

1 answer:

barxatty [35]3 years ago

7 0

Step-by-step explanation:

5x64=32066=(320+x} 666x6={320+x)396=320+x=396-320

You might be interested in

I will mark you brainlist!

Zigmanuir [339]

Answer:

C is the answer

Step-by-step explanation:

7 0

3 years ago

Which equation represents the line if m=-3/4 and b=2? (1 Point) O y=-2 + 2 x O x + 2 = 12 y = -x + 2 O y = - 2 x - 2

nevsk [136]

Answer:

y = -3/4x + 2

Step-by-step explanation:

Line formula in slope-intercept form:

y = mx + b

Given

m = -3/4, b = 2

Then the formula is:

y = -3/4x + 2

None of the answer options match this

3 0

3 years ago

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

3 years ago

Convert 1,230 minutes to hours.

4vir4ik [10]

$1h=60min\to1min=\dfrac{1}{60}h\\\\1,230min=\dfrac{1}{60}\cdot1,230h=\dfrac{1,230}{60}h=\dfrac{123}{6}h=20.5h\\\\Answer:\boxed{20.5}\to\fbox{d.}$

8 0

3 years ago

Read 2 more answers

I want the answer only, Due now.

klio [65]

Answer:

Write the equation then try the equation with the numbers from choice A then go down. do all of them. which ever ends up equal is the right answer.

Step-by-step explanation:

I will do the math but you try it first, then ill do the math step by step in the comments, but only if you try it first. im trusting you to try.

5 0

3 years ago