Answer:
He walks 1,060 miles on the tremil in one year.
Step-by-step explanation:
4*5=20*53=1,060
There are 53 sometimes 52 weeks in a year,2020 wise 53 so 53*20=1,060 miles.
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
First you need to distribute the -8
So you would get -8x-8 now distribute the 3 so it would be 3x-6
-8x-8+3x-6=-3+2 is how it should look
Now combine the -8x and 3x cause their like terms and also -8 and -6
-5x-14=-3x+2 now add -3 to both sides
-2x-14=2 and add 14 to both sides
-2x=12 all left to do is divide both by -2
X=-6
Answer:
At 1% significance level, this difference is considered to be extremely statistically significant.
Step-by-step explanation:
Group Group One Group Two
Mean 41.300 54.800
SD 6.800 6.000
SEM 2.050 1.604
N 11 14
H0: Mean of group I = Mean of group II
Ha: Mean of group I < mean of group II
(Left tailed test at 1% significance level)
The mean of Group One minus Group Two equals -13.500
standard error of difference = 2.563
t = 5.2681
df = 23
p value= 0.00005
Since p < significance level, reject H0
Given:
Area(A)= 63m^2
Length (L)= 2W+5
Width (W)=?
A=LxW
63=(2W+5)(W)
63=2W^2 + 5W
0=2W^2+5W-63
0=(2W-9)(W+7)
2W-9=0 then W=4.5 and W+7=0 then W=-7
Can only use 4.5 since it is positive and distance is positive.
W= 4.5 m
L=2W+5=2 (4.5)+5=9+5=14m
