it shoudl be : 2Fe(NO3)3 + 3MgSO4 → 3Mg(NO3)2 + Fe2(SO4)3
(the difference is Fe2(SO4)3 has no coefficient)
<span>my answer is B.The electrical charge of the hydrogen atom is thought to be exactly zero. This is a consequence of the apparent equality of the magnitude of the electrical charges of the electron and the proton, and their opposite sign. The electrical charge of neutral atoms has been measured to be zero, with an uncertainty of something like 10^(-20) e, where e is the elementary charge.</span>
The mass in grams of NH₃ produced from the reaction is 3.4 g
<h3>Balanced equation</h3>
We'll begin by writing the balanced equation for the reaction. This illustrated below:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
<h3>How to determine the volume of NH₃ produced</h3>
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
Therefore,
2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃
<h3>How to determine the mass of NH₃ produced</h3>
We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:
22.4 dm³ = 1 mole NH₃
Therefore,
4.48 dm³ = 4.48 / 22.4
4.48 dm³ = 0.2 mole of NH₃
Finally, we shall determine the mass of NH₃ as follow:
- Molar mass of NH₃ = 17 g/mol
- Mole of NH₃ = 0.2 mole
- Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 0.2 × 17
Mass of NH₃ = 3.4 g
Learn more about stoichiometry:
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Answer:
m= 6.9905 = 7 g
Explanation:
The formula is m= M.n
m= mass (g), M= Molar mass (g/mole), n= moles (moles)
Molar mass of Cu is 63.55
=) m= 63.55*0.11
m= 6.9905 = 7 g
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