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Verizon [17]
3 years ago
9

Which of the following would be a good use for a nonmetal? handle of frying pan electrical wires structural components in buildi

ngs coinage
Chemistry
2 answers:
lora16 [44]3 years ago
7 0

Handle of frying pan would be a good use for a nonmetal. A nonmetal is neither a good thermal insulator nor a good electrical conductor. Because it is neither, it can be use as a semiconductor. It does not absorb heat that much that is why it is best in insulating.

Rasek [7]3 years ago
6 0

Answer: Option (a) is the correct answer.

Explanation:

Non-metals are the substance which are electron deficient in nature. They are also brittle and bad conductors of heat and electricity.

Whereas electrical wires, structural components in buildings, and coinage requires good conductors of heat and electricity. Therefore, metals being good conductors of heat and electricity are suitable for them.

Hence, we can conclude that handle of frying pan would be a good use for a non-metal.

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Can anyone answer this? I'd appreciate it. :0
Ganezh [65]

Answer:

Triclinic crystal forms. Also known as the rhombohedron system, its shape is three dimensional like a cube, but it has been skewed or inclined to one side making it oblique. All crystal faces are parallel to each other. A rhombohedral crystal has six faces, 12 edges, and 8 vertices.

bascially short answer is 6 faces

8 0
3 years ago
Read 2 more answers
If gas in a sealed container has a pressure of 50 kpa at 300 k, what will the pressure be if the temperature rises to 360 k? 161
Illusion [34]

60 \; \text{kPa}

The pressure an ideal gas exerts on a sealed container of fixed volume is directly related to its temperature in degrees Kelvin. That is:

T_1 / T_2 = P_1 / P_2

In this scenario:

  • T_1 = 300 \; \text{K}
  • P_1 = 50 \; \text{kPa}
  • T_2 = 360 \; \text{K}

Rearranging gives

\begin{array}{lll}P_2 &=& P_1 \cdot T_2 / T_1 \\ &=& 50 \; \text{kPa} \times (360 \; \text{K})/ (300 \; \text{K})\\ &=& 60 \; \text{kPa}\end{array}


6 0
3 years ago
Hi :) how to do 4(b)?
boyakko [2]
When acid and base solutions react, they produce water and a neutral ionic compound called a salt. The reaction is called a neutralization reaction.
8 0
3 years ago
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For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is 110. kJ. Calculate the equlilibriunm c
mestny [16]

Answer:

Explanation:

The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:

ΔG = -RT ln K

<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>

<em />

Replacing (110kJ = 110000J):

110000J/mol = -8.314J/molK*303.15K ln K

-43.644 = lnK

1.11x10⁻¹⁹ = K

<em />

7 0
3 years ago
Consider the reaction:
stich3 [128]

Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

7 0
3 years ago
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