An object weighting 9.6 grams is placed in a graduated cylinder displacing the volume from 10.0mL to 13.2 mL
1 answer:
The volume of object is 3.2 ml
<h3>Explanation:</h3>Given:
Mass of the object = M = 9.6 g
Initial volume of liquid:
Final volume of liquid after displacement:
Total volume of the displaced object inside a graduating cylinder will be given as difference between the final volume and initial volume of the expanding object.
V = 3.2 ml
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Answer:
Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
element & mass %
phosphorus & 39.18%
sulfur & 60.82%
Write the molecular formula of X.
Explanation:
The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.
Empirical formula calculation:
element: phosphorus sulfur
co9mposition: 39.185% 60.82%
divide with
atomic mass: 39.185/31.0 g/mol 60.82/32.0g/mol
=1.26mol 1.90mol
smallest mole ratio: 1.26mol/1.26mol =1 1.90mol/1.26 mol =1.50
multiply with 2: 2 3
Hence, the empirical formula is:
P2S3.
Mass of empirical formula is:
158.0g/mol
Given, molecule has molar mass --- 316.25 g/mol
Hence, the ratio is:
316.25g/mol/158.0 =2
Hence, the molecular formula of the compound is :
2 x (P2S3)
=
<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is
<u>Explanation:</u>
The diameter of the molecule will be equal to the uncertainty in position.
The equation representing Heisenberg's uncertainty principle follows:
where,
= uncertainty in position = d =
= uncertainty in momentum =
m = mass of oxygen molecule =
h = Planck's constant =
Putting values in above equation, we get:
Hence, the uncertainty in the velocity of oxygen molecule is