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3 years ago

Need help fast 50 points Project: Creating a Morphological Matrix

Engineering

1 answer:

Leokris [45]3 years ago

7 0

Answer:

The fundamental difference between effective and less effective matrix organizations is whether the tension between different perspectives is creative or destructive. While various processes, systems and tools can help, what matters most is what top leadership says and does and how that flows through the organization in shared targets, clear accountabilities, live team interactions and team-building transparency and behaviors.

Getting matrix management right is linked inextricably to an organization’s culture - the only sustainable competitive advantage. Key components of a culture can be grouped into behaviors, relationships, attitudes, values and the environment.

Environment and values: Each organization has its own environment, context and bedrock values. Everyone needs to know what matters and why. Don’t try to do anything else until you’ve got that set.

Attitude is about choices: An organization’s overall strategy drives choices about which of its parts will be best in class (superior), world class (parity), strong (above average), or simplified/outsourced to be good enough. These choices help determine the need for a matrix and how best to design it.

Relationships and behaviors: This is why organizations have matrices. The most effective of them best balance focus and collaboration. They allow leaders and teams to build differential strengths and then work together to make the best possible decisions and scale enterprises with a creative tension that they could not do on their own.

My colleague Joe Durrett has worked all sides of matrix organizations in marketing at Procter & Gamble, sales and general management at Kraft General Foods and CEO of Information Resources, Broderbund Software and Advo. He has seen matrices at their best and at their worst and offered his perspective for this article along with his partners John Lawler and Linda Hlavac. The 12 ways to make matrix organizations more effective were built on their ideas.

Explanation:

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You are given a rectangular piece of cloth with dimensions X by Y, where X and Y are positive integers, and a list of n products

Bond [772]

The proof that recursion is exponential and that dynamic programming is polynomial is given by the formula;

P(x,y) = max{

P(x,y)

max (1 <= h <= X) { P[h, Y] + P(X - h, Y) }

max (1 <= v <= Y) { P[X, v] + P[X, Y - v] }

}

To prove that the recursion is exponential and that dynamic programming is polynomial. we will do so as follows;

Let us first have the assumption that the cloth is in such a manner that either way, a product can be oriented. This implies that that after a cut, we will now have two pieces of cloth.

Now, we will make a list of the side lengths of the products that can fit in the piece after which we will consider a vertical cut for each of the side length as well as a horizontal cut for each of the side length, then we apply the same algorithm to each of the two resulting pieces.

Thus, after the point above, it is likely true that in some instances, there may be a place to cut that is not at a product side length. However, It might be better for us to make a list of lengths composed of one or more pieces side by side as long as the sum is less than the length of the side being considered.

Lastly, we would note that this recursive approach is not limited to just two -dimensional problems as It could also be applied to a single or more than two dimensions. A useful proof would be to prove it for one dimension, then assuming it is true for n dimensions, prove it is true for n + 1 dimensions.

Thus;

P(x,y) = max{

P(x,y)

max (1 <= h <= X) { P[h, Y] + P(X - h, Y) }

max (1 <= v <= Y) { P[X, v] + P[X, Y - v] }

}

Read more at; brainly.com/question/11665190

3 0

3 years ago

The A-36 steel drill shaft of an oil well extends 12 000 ft into the ground. Assuming that the pipe used to drill the well is su

sladkih [1.3K]

check photo solvecheck photo solve

3 0

3 years ago

A 900 kg car is accelerated from a speed of 10 m/s to 30 m/s. An estimated heat loss of 20 BTU's occurs during the acceleration.

Strike441 [17]

Answer:

Work = 651,1011 kJ

Explanation:

Let´s take the car as a system in order to apply the first law of thermodynamics as follows:

$E_{in}- E_{out}=E_{system,final}- E_{system,initial}$

Where

$E_{in}- E_{out}=(Q_{in}-Q_{out})_{heat}+(W_{in}-W_{out})_{work}+(Em_{in}-Em_{out})_{mass}$

And considering that there is no mass transfer and that the only energy flows that interact with the system are the heat losses and the work needed to move the car we have:

$E_{in}- E_{out}=-Q_{out}+W_{in}$

Regarding the energy system we have the following:

$E_{system,final}- E_{system,initial}=(U_{f}-U_{i})_{internal}+(1/2m(V^2_{f}-V^2_{i}))_{kinetic}+(mg(h_{f}-h_{i}))_{potential}$

By doing the calculations we have:

$E_{system,final}- E_{system,initial}=[0,1*900]_{internal}+[0,5*900(30^2-10^2)/1000)_{kinetic}+(900*10*(20-0)/1000)_{potential}\\E_{system,final}- E_{system,initial}=90+360+180=630kJ$

Consider that in the previous calculation, the kinetic and potential energy terms were divided by 1.000 to change the units from J to kJ.

Finally, the work needed to move the car under the required conditions is calculated as follows:

$W_{in}=Q_{out}+E_{system,final}- E_{system,initial}\\W_{in}=21,1011+630=651,1011kJ$

Consider that in the previous calculation, the heat loss was changed previously from BTU to kJ.

4 0

3 years ago

g Three unequal point masses are attached to a vertical shaft with light rods. Two masses, m and 3m, are at a distance a from th

Alexxandr [17]

Answer:

12ma²

Explanation:

The moment of inertia I = ∑mr² where m = mass and r = distance from shaft

Since we have three masses,

So, I = m₁r₁² + m₂r₂² + m₃r₃² where m₁ = first mass = m, m₂ = second mass = 3m and m₃ = third mass = 2m. Also, r₁ = distance of first mass from shaft = a, r₂ = distance of second mass from shaft = a and r₃ = distance of third mass from shaft = 2a.

I = m₁r₁² + m₂r₂² + m₃r₃²

I = ma² + 3ma² + 2m(2a)²

I = ma² + 3ma² + 2m(4a²)

I = ma² + 3ma² + 8ma²

I = 12ma²

4 0

3 years ago

ANSWER ASAP<br> What is the point system?<br> this is for driving

lara31 [8.8K]

Answer:

A point system assigns point values to traffic violations for each state. When the DMV receives a conviction notice from the court, the offense is entered on your driving record and points are assigned. These points are counted during a specified time period.

Explanation:

3 0

3 years ago