we want to make a schottky diode on one surface of an n-type semiconductor, and an ohmic contact on the other side. the electron
affinity is 5ev, band gap is 1.5ev, and the fermi potential is 0.25ev?
1 answer:
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Answer:
- F1.x ≈ -28.93
- F1.y ≈ 34.47
- F2.x = 70
- F2.y = 0
- (F1+F2).x ≈ 41.07
- (F1+F2).y ≈ 34.47
- |F1+F2| ≈ 53.62
- ∠(F1+F2) ≈ 40.0°
Explanation:
A suitable calculator can show you the vector components and their resultant in polar or rectangular format. (See attached.) 2D vectors are conveniently treated as complex numbers, which is why the y-component values are shown as imaginary.
(The 50° angle measured from the -x axis is equivalent to 130° measured from the +x axis, which is the reference we're using here.)
If you'd like to compute the vector components by hand, they are ...
(x, y) = magnitude×(cos(angle), sin(angle))
This notation is sometimes abbreviated <em>magnitude cis angle</em>, a reference to the complex number form x+yi.
Answer:
Power required to overcome aerodynamic drag is 50.971 KW
Explanation:
For explanation see the picture attached
