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Bumek [7]
3 years ago
11

Use the Hurricanes data and via Multiple regression select the three input variables: Min-pressure, Gender, Category in order to

predict the All-Deaths. Pick one of the three variables that has the best P-value and re-do the regression using ONLY this one variable to predict the All-deaths. Answer the questions. (Numerical answers are rounded so choose the answer that matches the best).
Engineering
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

Answer for the question:

Use the Hurricanes data and via Multiple regression select the three input variables: Min-pressure, Gender, Category in order to predict the All-Deaths. Pick one of the three variables that has the best P-value and re-do the regression using ONLY this one variable to predict the All-deaths. Answer the questions. (Numerical answers are rounded so choose the answer that matches the best).

is explained in the attachment.

Explanation:

Download pdf
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zener shunt regulator employs a 9.1-V zener diode for which VZ = 9.1 V at IZ = 9 mA, with rz = 40 and IZK= 0.5 mA. The available
gulaghasi [49]

Answer:

V_z=9.1v

V_{zo}=8.74V

I=10mA

R=589 ohms

Explanation:

From the question we are told that:

Zener diode Voltage V_z=9.1-V

Zener diode Current I_z=9 .A

Note

rz = 40\\\\IZK= 0.5 mA

Supply Voltage V_s=15

Reduction Percentage P_r= 50 \%

Generally the equation for Kirchhoff's Voltage Law is mathematically given by

V_z=V_{zo}+I_zr_z

9.1=V_{z0}+9*10^{-3}(40)

V_{zo}=8.74V

Therefore

At I_z-10mA

V_z=V_{z0}+I_zr_z

V_z=8.74+(10*10^{-3}) (40)

V_z=9.1v

Generally the equation for Kirchhoff's Current Law is mathematically given by

-I+I_z+I_l=0

I=10mA+\frac{V_z}{R_l}

I=10mA+\frac{9.1}{0}

I=10mA

Therefore

R=\frac{15V-V_z}{I}

R=\frac{15-9.1}{10*10^{-3}}

R=589 ohms

5 0
3 years ago
When a man returns to his well-sealed house on a summer day, he finds that the house is at 35°C. He turns on the air conditioner
ipn [44]

Answer:

\dot W = 1.667\, kW

Explanation:

A well-sealed house means that there is no mass interaction between air indoors and outdoors. Hence, cooling process is isochoric. The heat removed by the air conditioner is:

\dot Q_{L} = \frac{m_{air}}{\Delta t} \cdot c_{v, air} \cdot (T_{o}-T_{f})\\\dot Q_{L} = \frac{800\, kg}{(30\, min)\cdot (\frac{60\, s}{1 \, min} )}\cdot (0.7 \frac{kJ}{kg \cdot K}) \cdot (15\, K)\\\dot Q_{L} = 4.667\, kW

The power drawn by the air conditioner is:

\dot W = \frac{\dot Q_{L}}{COP_{R}} \\\dot W = \frac {4.667\, kW}{2.8}\\\dot W = 1.667\, kW

3 0
3 years ago
SSL/TLS is used for ________.
Nana76 [90]

Answer:

1.Originally developed by Netscape, SSL is an Internet security protocol used by Internet browsers and Web servers to transmit sensitive information. SSL has become part of an overall security protocol known as Transport Layer Security (TLS). SSL/TLS can be used for Web applications

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4. Converting application messages into bits is called encoding

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8. The general name for malware on a user's PC that collects sensitive information and sends this information to an attacker is SPYWARE

9. Firewall log files should be read EVERYDAY

10. When a firewall identifies an attack packet, it both discards the packet and copies information about the packet into a log file

11. IT security employees are the most difficult employees

12. In authentication, the SUPPLICANT is the party trying to prove his or her identity.

13. In a firewall, VPN traversal reduces firewall filtering effectiveness

14. DIRECTLY-PROPAGATING WORM can spread more rapidly

15 UDP is an unreliable, connectionless transport layer protocol that provides message-based data transmission. TCP is an example of connection-oriented protocols.

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17. 802.11 data link layer standards govern neither access point operation nor frame organization

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4 0
4 years ago
Air expands through a turbine from 10 bar, 900 K to 1 bar, 500 K. The inlet velocity is small compared to the exit velocity of 1
Elis [28]

Answer:

- the mass flow rate of air is 7.53 kg/s

- the exit area is 0.108 m²

Explanation:

Given the data in the question;

lets take a look at the steady state energy equation;

m" = W"_{cv / [ (h₁ - h₂ ) -\frac{V_2^2}{2} ]

Now at;

T₁ = 900K, h₁ = 932.93 k³/kg

T₂ = 500 K, h₂ = 503.02 k³/kg

so we substitute, in our given values

m" = [ 3200 kW × \frac{1\frac{k^3}{s} }{1kW} ] / [ (932.93 - 503.02  )k³/kg  -\frac{100^2\frac{m^2}{s^2} }{2}|\frac{ln}{kg\frac{m}{s^2} }||\frac{1kJ}{10^3N-m}| ]

m" = 7.53 kg/s

Therefore, the mass flow rate of air is 7.53 kg/s

now, Exit area A₂ = v₂m" / V₂

we know that; pv = RT

so

A₂ = RT₂m" / P₂V₂

so we substitute

A₂ = {[ (\frac{8.314}{28.97}\frac{k^3}{kg.K})×500 K×(7.54 kg/s) ] / [(1 bar)(100 m/s )]} |\frac{1 bar}{10N/m^2}||10^3N.m/1k^3

A₂ = 0.108 m²

Therefore, the exit area is 0.108 m²

8 0
3 years ago
A stream of vinyl chloride monomer (VCM, H2C=CHCl, molecular weight = 62.5lb/lb-mol) in air is being produced from a process to
Andreas93 [3]

Question:

The question is incomplete. The table of value was not added to your question. Below is the table of value and the plotted graph attached.

p          R= VCM/AC               p/R

0.0001          1                    0.0001

0.0005        1.7                   0.000294

0.001          3                   0.000333

0.005          6                   0.000833

0.01            8                   0.00125

0.05          10                   0.005

Answer:

(a) Yes

(b) W.C = 9.1428

(c) mass of activated carbon = 27.35 Ib-mole/activated carbon

Explanation:

(a) From the graph attached, it is evident that Langmuir isotherm fits the data well. So, the answer is yes.

 

(b)

Since the input stream has a VCM partial pressure of 0.02 psia, this would be used to find working capacity of activated carbon.

From the graph it can be found by interpolation that p/R value corresponding to 0.02 psia is 0.0021876. Thus R = 9.1428 = WC

It should be noted that in adsorption process, activated carbon is in equilibrium with 0.001 psia of VCM. Thus, from the data R= 1 i.e. this amount of VCM is not adsorbed and lost. This value may be deducted based on the definition of working capacity (WC).

(c)

The molar flow rate of VCM = 1000*62.3*0.02/379*60*14.7

                                               = 0.003739 Ib-mole/hr

Mass of activated carbon required = 0.003739 *8*9.1428*100

                                   = 27.35 Ib-mole/AC

3 0
3 years ago
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