Water vapor and carbon dioxide!
Explanation:
thermal expansion ∝L = (δL/δT)÷L ----(1)
δL = L∝L + δT ----(2)
we have δL = 12.5x10⁻⁶
length l = 200mm
δT = 115°c - 15°c = 100°c
putting these values into equation 1, we have
δL = 200*12.5X10⁻⁶x100
= 0.25 MM
L₂ = L + δ L
= 200 + 0.25
L₂ = 200.25mm
12.5X10⁻⁶ *115-15 * 20
= 0.025
20 +0.025
D₂ = 20.025
as this rod undergoes free expansion at 115°c, the stress on this rod would be = 0
Answer:
You have to know the basic mechanics to help you correctly use the motorcycle, and you also have to have the right mindset - knowing you can ride it, and having determination. All of these factors are the primary mental skills you need for riding a motorcycle.
Answer:
eccentrcity of orbit is 0.22
Explanation:
GIVEN DATA:
Initial velocity of satellite = 8333.3 m/s
distance from the sun is 600 km
radius of earth is 6378 km
as satellite is acting parallel to the earth therefore
and radial component of given velocity is zero
we have
h = 6.97*10^6 *8333.3 = 58.08*10^9 m^2/s
we know that
so
solvingt for 
therefore eccentrcity of orbit is 0.22
Answer:
Given,
Temperature;
T = 393;;K
Convert to Celcius;
T = (393-273) degrees
T = 120°C
Using Table A-4 (Saturated water - Temperature table), at T = 120 C;
vf = 0.001060 m³/kg
vg = 0.89133 m³/kg
Quality is given as;
75% = 0.75
Specific volume is given as;
v = vf + x (vg - vf) = 0.001060 + 0.75(0.89133 _ 0.001060)
v= 0.66876 m³/kg
We know;
v = V/m
0.66876 = 100/m
m = 149.53 kg
