Answer:
83.60 J/k mol
Explanation:
The molar entropy of vaporization,ΔS vap is given by the expression:
ΔS vap = ΔHvap / Tb where
ΔHvap = molar enthalpy change of vaporization, J/mol
Tb = boiling temperature, K
We have both ΔHvap, and Tb so lets solve our question.
T= (23.8 + 273) = 296.8 K
ΔHvap = 24.8 kJ = 24.8 x 10³ J
ΔS vap = ΔHvap / Tb = 24.8 x 10³ J/mol / 296.8 K = 83.6 J/k mol
