Answer:
Explanation:
We have given the radius of first sphere is 10 cm and radius of second sphere is 20 cm
So the potential of first sphere will be greater than the potential of the second sphere, so charge will flow from first sphere to second sphere
Let q charge is flow from first sphere to second sphere and then potential become same
So
200-100=2q+q
So
We know that potential energy U=qV
<span>It does not matter how heavy the object is, as long as there is no drag or wind interference (such as wind on a feather or piece of paper) the gravitational pull will be equal, therefore the answer is 9s.</span>
<span>Every falling object on Earth will experience air resistance,
unless it's falling inside a vacuum chamber.
The air resistance will increase as the speed of the falling object
increases.
At the point when the air resistance equals the weight, there is no
acceleration, and the object will fall with constant speed after that.</span>
The answer that you are looking for is D.
Answer:
-3.396 m/s or 3.465 m/s
Explanation:
v = Speed of sound in air = 343 m/s
= Relative speed of the singer
f = Observed frequency
f' = Actual frequency
1% change can mean
From the Doppler effect equation we have
The velocity is -3.396 m/s
when
The velocity is 3.465 m/s