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3 years ago

15 POINTS! ANSWER CORRECTLY FOR BRAINLIEST!

Physics

2 answers:

Minchanka [31]3 years ago

5 0

Answer:

Explanation: I agree with A

igor_vitrenko [27]3 years ago

5 0

Credit: Larus (Full Credits to Larus I didn't make this answer)

The correct answer is that it is too high for the weather balloons.

The mesosphere refers to the layer of the atmosphere of the Earth. It is present directly above the stratosphere and below the thermosphere. It elongates from about 50 to 85 kilometers above the Earth. The coldest temperatures in the atmosphere of the Earth, that is, around -90 degree C, is found close to the top of the layer.

It is tough to study mesosphere, therefore, less is known about the layer of the atmosphere in comparison to the other layers. It is tough as weather balloons cannot fly high enough to reach the mesosphere. The satellites orbit above the mesosphere, and cannot directly determine the traits of the layer.

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How much work is required for a 74 kg sprinter to accelerate from rest to 2.2 m/s?

My name is Ann [436]

Answer:

179.1 kg

Explanation:

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2 years ago

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a shot putter accelerates a 7.3kg shot from rest to 14m/s in 1.5r seconds. what average power was developed?

Sedaia [141]

Explanation:

$power = \frac{energy \: expended}{time}$

m = 7.3kg

u = 0

v = 14m/s

t = 1.5sec

P = (0.5×7.3×14²) ÷ 1.5

P = 476.93

P = 477 watt

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4 years ago

In a car collision, is it better for the passenger if the change in momentum is over a short period of time or a long period of

e-lub [12.9K]

Explanation:

The force on the passenger will be F = ma

Here, m does not change, but a is the variable.

If the cars slows down very fast, the acceleration will be higher, and thus the force will be higher.

If the acceleration is lower, the force will be lower as well, which would be the most desirable scenario for the passenger.

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3 years ago

Suppose the line on a distance-versus-time graph and the line on a speed-versus-time graph are both slanted straight lines going

lesya [120]

No, because the distance-time would show a constant velocity but the velocity-time graph shows an increasing velocity.

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4 years ago

600 kg elephant runs at 5 m/s and jumpts onto a 100kg cart. If the coefficient of friction is .04 how far will the cart travel o

Minchanka [31]

Answer:

Eleven seconds.

Explanation:

Two keys are needed to solve this problem. First, the conservation of momentum: allowing you to calculate the cart's speed after the elephant jumped onto it. It holds that:

$m_ev_e+m_c\cdot0=(m_e+m_c)v_0\implies \\v_0=\frac{m_ev_e}{m_e+m_c}=\frac{600kg\cdot 5\frac{m}{s}}{700kg}=4.29\frac{m}{s}$

So, once loaded with an elephant, the cart was moving with a speed of 4.29m/s.

The second key is the kinematic equation for accelerated motion. There is one force acting on the cart, namely friction. The friction acts in the opposite direction to the horizontal direction of the velocity v0, its magnitude and the corresponding deceleration are:

$F_r = 0.04\cdot (m_e+m_c)g\implies a_r = 0.04\cdot g= 0.04 \cdot 9.8 \frac{m}{s^2}=0.39\frac{m}{s^2}$

The kinematic equation describing the decelerated motion is:

$v = -a_r t+v_0\\0 = -a_rt+v_0\implies \\t = \frac{v_0}{a_r}=\frac{4.29\frac{m}{s}}{0.39\frac{m}{s^2}}=11s$

It takes 11 seconds for the comical elephant-cart system to come to a halt.

7 0

4 years ago