3 years ago

Select the correct answer.

Chemistry

1 answer:

mr_godi [17]3 years ago

7 0

Answer:

No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal.

Hope this helps!

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In a soil profile, which is the second layer? solid rock subsoil parent rock topsoil

taurus [48]

Subsoil is the layer of soil under the topsoil on the surface of the ground.

7 0

3 years ago

does the nitro group on the pyridine ring make the ring more electron rich or more electron deficient

Arte-miy333 [17]

Answer:

more electron deficient

Explanation:

The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.

This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

3 0

2 years ago

Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C

umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

$K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}$

Given:

$\left[I_2_{Equilibrium} \right]$ = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

$0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}$

So,

$\left[I_{Equilibrium} \right]^2=0.011\times 0.10$

$\left[I_{Equilibrium} \right]^2=0.0011$

$\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M$

Thus, The concentration of I at equilibrium = 3.3166×10⁻² M

3 0

3 years ago

HELPPP PLS

photoshop1234 [79]

I think it could be C maybeee though

6 0

3 years ago

If 1.00L of water is added to 3.00 L

Bezzdna [24]

Answer:

4.5M

Explanation:

Here is why:

6 0

2 years ago