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enyata [817]
3 years ago
11

During an experiment, distilled water was placed in a sealed container and the container was heated gradually. Describe this sys

tem when it reaches phase equilibrium. (10 points)
Chemistry
1 answer:
Bumek [7]3 years ago
6 0

Explanation:

At first, the container just contains a liquid phase. As the temperature rises, so does the pressure, as well as a liquid-vapor phase equilibrium is created. If we heat it past boiling point, it reaches the crucial stage at 3740C and 217.7 atm pressure, when the border between the two phases vanishes and just a single phase remains, known as liquid phase.

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Based on the results from this experiment, predict whether some of the following combinations of compounds would precipitate or
iren [92.7K]

Answer:

* No precipitate: LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)

* Precipitate: 3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)

* Precipitate: MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)

Explanation:

Hello!

In this case, since these all are double displacement reactions, in which the cations and anions are exchanged, we can write the resulting chemical reactions as follows:

a. LiOH and NaCl: No precipitate is formed since LiOH and NaOH are both largely soluble in water:

LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)

b. BaCl2 and Na3PO4: barium phosphate precipitate is formed because it has a large molar mass which makes it insoluble in water:

3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)

c. MgSO4 and KOH: magnesium hydroxide "milky" precipitate is formed because it is not soluble in water:

MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)

Moreover, we can relate the solubility of a substance by considering its polarity, molar mass and nature; usually, heavy substances tend to be insoluble in water as well as nonpolar compounds.

Best regards!

6 0
3 years ago
A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions
Damm [24]

A 1. 00 ml sample of an unknown gas effuses in 11. 1 min. an equal volume of h2 in the same apparatus under the same conditions effuses in 2. 42 minutes then the molar mass of the unknown gas is 41.9.

Molar mass of H2 = 2

Molar mass of unknown gas = ?

rate 1 = 11.1

rate 2 = 2.42

<h3>What is graham law? </h3>

Graham's law states that the rate of diffusion or effusion of a given gas is inversely proportional to the square root of its molar mass.

By apply graham law

Rate1/rate2 = sqrt(MW2/MW1)

[\frac{rate1}{rate2} ]^{2} = \frac{MW2}{2} \\\\\\mw= 2[\frac{11.1}{2.42} ]^{2} \\\\= 20.97 X 2 \\\\= 41.9

Thus, we found that the molar mass of the unknown gas is 41.9.

Learn more about graham's law: brainly.com/question/12415336

#SPJ4

4 0
2 years ago
During photosynthesis, carbon dioxide, water, and energy react to form glucose and oxygen. Which line would be longer on the ene
timama [110]

Answer:

The vertical line indicating bonds breaking

Explanation:

3 0
2 years ago
How does a catalyst increase the rate of a reaction?
Norma-Jean [14]

Answer:

C) It provides a lower activation energy for the reaction is the correct answer.

Explanation:

  • A catalyst increases the rate of the chemical reaction by lowering the activation energy for a reaction.
  • Catalyst is used to increase the reaction rate, it remains unchanged in the chemical reaction and it does not change the equilibrium constant.
  • Activation energy is a minimum amount of energy required to initiate the reaction.

6 0
3 years ago
What determines the traits of offspring?A.Food sources that have been genetically engineered B.Literary metaphors and exciting c
iren2701 [21]

Answer:

D. Genes received from the offsprings parents.

Explanation:

8 0
3 years ago
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