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luda_lava [24]
3 years ago
7

A HIGH SPEED TRAIN IS 180M LONG AND IT IS TRAVELLING AT 50M/S.HOW LONG WILL IT TAKE TO PASS A PERSON STANDING AT A LEVEL CROSSIN

G?
B-HOW LONG WILL IT TAKE TO PASS COMPLETELY THROUGH A STATION WHOSE PLATFORMS ARE 220M IN LENGTH?
Physics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

a. Time = 3.6 seconds

b. Time = 4.4 seconds

Explanation:

Given the following data;

Distance = 180 m

Speed = 50 m/s

a. To find the time;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

Speed = \frac{distance}{time}

Making time the subject of formula, we have;

Time = \frac{distance}{speed}

Substituting into the equation, we have;

Time = \frac{180}{50}

Time = 3.6 seconds

b. Distance = 220 meters

Speed = 50 m/s

To find the time;

Time = \frac{distance}{speed}

Substituting into the equation, we have;

Time = \frac{220}{50}

Time = 4.4 seconds

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3 years ago
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Which type of carbohydrate is the body unable to digest, but is still important for lowering cholesterol, balances glucose level
AysviL [449]

Answer:

Cellulose

Explanation:

Cellulose is the carbohydrate which is unable to be digested by body. Adding fiber's (cellulose)  to one's diet reduces blood cholesterol level because soluble fiber  dissolves in water to form a gel, which moves slowly through the intestines binding up fat, dietary cholesterol, bile salts, and sugar to be excreted. Once excreted, these are no longer available to build more cholesterol. Also cellulose remains undigested but is effectively making one gain more calories, so it helps prevents over eating.

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3 years ago
Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.
scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

   Pressure at sea level = 1 atm = 101300 Pa

   we know

   P = ρ g h

   h = \dfrac{P}{\rho\ g}

   h = \dfrac{101300}{1.3\times 9.8}

          h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

  at x = 0  air density = 0

  at x= h   ρ_l = ρ_sl

 assuming density is zero at x - distance

 \rho_x = \dfrac{\rho_{sl}}{h}\times x

now, Pressure at depth x

dP = \rho_x g dx

dP = \dfrac{\rho_{sl}}{h}\times x g dx

integrating both side

P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx

P =\dfrac{\rho_{sl}\times g h}{2}

 now,

h=\dfrac{2P}{\rho_{sl}\times g}

h=\dfrac{2\times 101300}{1.3\times 9.8}

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height of the atmosphere is equal to 15902.67 m.

6 0
3 years ago
A ball is thrown downward from the top of a building with an initial speed of 25 m/s.
Bumek [7]

Answer:

h = 69.6 m

Explanation:

Data:

  • Vo = 25 m/s
  • t = 2.0 s
  • g = 9.8 m/s²
  • h = ?

Formula:

  • \boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}

Replace and solve:

  • \boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}
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  • \boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}
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The building has a height of <u>69.6 meters.</u>

Greetings.

5 0
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lions [1.4K]

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As, we know that the same charges repeal each other both of the balloons with be apart from each other.

This is due to the static electricity, the negatively charged particles jump to the positive one. When balloons are rubbed they become negatively charged.

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4 years ago
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