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monitta
4 years ago
12

Dos cargas con 2.8(×10-6) C y 7.5(×10-6) C respectivamente se atraen con una fuerza de 10 [N], ¿A qué distancia se encuentran se

paradas?
Physics
1 answer:
Anarel [89]4 years ago
3 0

Answer:

r = 0.137 m

Explanation:

The electric force is given by the Coulomb equation

          F = k q₁ q₂ / r²

where k is the constant of Coulomb that is worth 8,988 10⁹ N m²/C², q₁ and q₂ are the charges and r is the distance that separates them

         r² = k q₁q₂ / F

         r = √ k q₁q₂ / F

let's calculate

         r = √ (8.99 10⁹ 2.8 10⁻⁶ 7.5 10⁻⁶⁶ / 10

         r = √ (1,8879 10⁻²)

         r = 0.137 m

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