Question

A ball is thrown downward from the top of a building with an initial speed of 25 m/s.

Answer 1

Answer:

h = 69.6 m

Explanation:

Data:

• Vo = 25 m/s
• t = 2.0 s
• g = 9.8 m/s²
• h = ?

Formula:

• $\boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}$

Replace and solve:

• $\boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}$

• $\boxed{\bold{h=50\frac{m}{s^{2}}+\frac{9.8\frac{m}{s^{2}}*4\ s^{2}}{2}}}$

• $\boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}$

• $\boxed{\bold{h=50\ m+19.6\ m}}$

• $\boxed{\boxed{\bold{h=69.6\ m}}}$

The building has a height of 69.6 meters.

Greetings.