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3 years ago

A ball is thrown downward from the top of a building with an initial speed of 25 m/s.

Physics

1 answer:

Bumek [7]3 years ago

5 0

Answer:

h = 69.6 m

Explanation:

Data:

Vo = 25 m/s
t = 2.0 s
g = 9.8 m/s²
h = ?

Formula:

$\boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}$

Replace and solve:

$\boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}$

$\boxed{\bold{h=50\frac{m}{s^{2}}+\frac{9.8\frac{m}{s^{2}}*4\ s^{2}}{2}}}$

$\boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}$

$\boxed{\bold{h=50\ m+19.6\ m}}$

$\boxed{\boxed{\bold{h=69.6\ m}}}$

The building has a height of 69.6 meters.

Greetings.

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