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topjm [15]
3 years ago
7

1. What have modern observations shown sunspots to be?

Physics
1 answer:
tiny-mole [99]3 years ago
4 0

Answer:

.

Explanation:

sunspots are areas that appear dark on the sun's surface.They appear dark because they are colder that parts of the sun's surface. However, the temperature of a sunspot is still very high. This can cause a sudden burst of energy space. If a solar flare is very intense, the radiation it releases can interfere with our radio communication here on earth

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Do you think radio waves and x-rays are types of light?
goblinko [34]

Answer:

yes, radio waves and x-rays are type of light.

6 0
3 years ago
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Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c
11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}

And plug in the numbers we are given:

\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}

Learn more about ideal gases: brainly.com/question/26450101

5 0
3 years ago
A firecracker sitting on the ground explodes into two pieces. Immediately after the explosion, one of the pieces has momentum of
Misha Larkins [42]

Answer:

other part will move with momentum 0.5 kg m/s towards west

Explanation:

As we know that the during the explosion event the time interval is very small and there is no impulsive force on the firecracker during this time

so here we can say that the momentum will remains conserved during the this event

now if the initial momentum of the firecracker is zero

then the final momentum must be zero

so here we can say

P_1 + P_2 = 0

P_1 = 0.5 kg m/s towards east

now from above equation

P_2 = - P_1 = -0.5 kg m/s

so the other part will move with momentum 0.5 kg m/s towards west

6 0
4 years ago
In the process of electricity, what flows through the wires?
MAVERICK [17]
I think the answer would be
C.Electrons
Hope this helps

3 0
3 years ago
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Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.
MissTica

Answer:

Sorry I I’m a little lost

Explanation:

5 0
3 years ago
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