All categories

3 years ago

In the process of electricity, what flows through the wires?

Physics

2 answers:

diamong [38]3 years ago

5 0

Electrons flow through the wires, and you can remember this by the

"Elec" tricity and "Elec" trons

MAVERICK [17]3 years ago

3 0

I think the answer would be
C.Electrons
Hope this helps

You might be interested in

What is the surface area to volume ratio of this cube

Ipatiy [6.2K]

The edge of the cube is 5 cm.
The volume of the cube is (5cm) · (5 cm) · (5 cm) = (5 cm)³ = 125 cm³

The cube has 6 faces.
The area of each face is (5 cm) · (5 cm) = 25 cm²
The area of all 6 faces is (6) · (25 cm²) = 150 cm²

The ratio of its volume to its surface area is
the ratio of

(125 cm³) to (150 cm²)

= 5/6 cm⁻¹ .

3 0

4 years ago

PLEASE HELP MEEEEEEEEE T.T

elena55 [62]

By the way the link doesn’t work

4 0

3 years ago

If the maximum acceleration that is tolerable for passengers in a subway train is 1.39 m/s2 and subway stations are located 780

a_sh-v [17]

Answer:

The maximum speed a subway train can attain between stations is 32.93 m/s.

Explanation:

Given;

maximum tolerable acceleration = 1.39 m/s²

distance between subway train, d = 780 m

The distance available to accelerate between stations = ¹/₂ x 780 m = 390 m

Apply the following kinematic equation to determine the maximum speed;

v² = u² + 2ad

v² = 0 + 2ad

v² = 2(1.39)(390)

v² = 1084.2

v = √1084.2

v = 32.93 m/s

Therefore, the maximum speed a subway train can attain between stations is 32.93 m/s.

6 0

4 years ago

A block of inertia m is placed on an inclined plane that makes an angle θ with the horizontal. The block is given a shove direct

Wittaler [7]

Answer:

A) d = v² / (2g (μ cos θ + syn θ) B) μ = tan θ

Explanation:

Part A

We can work this part with the work and energy theorem, where the work of the friction forces is equal to the energy change of the system.

The work is

W = fr .d

With the force of friction it opposes the movement

W = - fr d

The energy at the lowest point is

Em₀ = K = ½ m v²

The energy at the highest point

$Em_{f}$ = U = m g y

The height (y) can be found by trigonometry

sin θ = y / d

y = d sin θ

W = $Em_{f}$ –Em₀

-fr d = mg d sin θ - ½ m v²

The equation for the force of friction is

fr = μ N

From Newton's second law

N - W cos Te = 0

We replace

-μ (mg cos θ) d - mg d sin θ = - ½ m v²

d g (μ cos θ + sin θ) = ½ v²

d = v² / (2g (μ cos θ + syn θ)

Part B

The block is stopped, what is the Angle tet, let's use Newton's second law

fr - W sin θ = 0 ⇒ fr = W sin θ

N - W cos θ= 0 ⇒ N = w cos θ

fr = μ N

μ (mg cos θ) = mg syn θ

μ = syn θ / cos θ

μ = tan θ

7 0

3 years ago

A thin, 100 g disk with a diameter of 8.0 cm rotates about an axis through its center with 0.15 J of kinetic energy. What is the

butalik [34]

Answer:

v=2.45 m/s

Explanation:

The rotational kinetic energy is calculated with:

$K=\frac{I\omega^2}{2}$

The moment of inertia of a disk is:

$I=\frac{mr^2}{2}$

A point on the rim of a disk will have a speed of:

$v=r\omega$

Putting all together:

$v=r\sqrt{\frac{2K}{I}}=r\sqrt{\frac{2(2K)}{mr^2}}=2\sqrt{\frac{K}{m}}$

Which for our values is:

$v=2\sqrt{\frac{0.15J}{0.1Kg}}=2.45m/s$

3 0

4 years ago

Read 2 more answers