The tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.
<h3>Principle of moments</h3>
The Principle of Moments states that when a body is in equip, the sum of clockwise moment about a point is equal to the sum of anticlockwise moment about the same point.
The formula for calculating moment is given below:
- Moment = Force × perpendicular distance from the pivot
<h3>Calculating the tension in the chains</h3>
From the principle of moments:
Let tension in chain 1 be T1 and tension in chain 2 be T2.
T1 + T2 = 150 + 650 + 419
T1 + T2 =1219
Taking all distances from chain 1,
Sum of Moments = 0
419 × 0.5 + 150 × 0.85 + 650 × 0.9 = T2 × 1.7
T2 = 922/17
T2 = 542.35 N
Then, T1 = 1219 - 542.35
T1 = 676.65 N
Therefore, the tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.
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Answer:
sorry i throght i had the answer
Explanation:
To find the ratio of planetary speeds Va/Vb we need the orbital velocity formula:
V=√({G*M}/R), where G is the gravitational constant, M is the mass of the distant star and R is the distance of the planet from the star it is orbiting.
So Va/Vb=[√( {G*M}/Ra) ] / [√( {G*M}/Rb) ], in our case Ra = 7.8*Rb
Va/Vb=[ √( {G*M}/{7.8*Rb} ) ] / [√( {G*M}/Rb )], we put everything under one square root by the rule: (√a) / (√b) = √(a/b)
Va/Vb=√ [ { (G*M)/(7.8*Rb) } / { (G*M)/(Rb) } ], when we cancel out G, M and Rb we get:
Va/Vb=√(1/7.8)/(1/1)=√(1/7.8)=0.358 so the ratio of Va/Vb = 0.358.
Answer:
the ball is rolling 7m/s
Explanation:
Formula for kinetic energy: 1/2mv²
K = 1/2mv²
98 = 1/2(4)v²
98 = 2v²
49 = v²
√49 = v
7 = v
