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MAVERICK [17]
2 years ago
13

TRUE or FALSE: Most Electromagnetic waves are blocked by the atmosphere. True False

Physics
1 answer:
wariber [46]2 years ago
6 0
True because the atmosphere is in the way
You might be interested in
How much heat in joules is required to melt an ice cube with a mass of 18.6 g at 0 °C? The Lf for water is 333 J/g.
EastWind [94]

Answer:

The heat energy required, Q = 6193.8 J

Explanation:

Given,

The mass of ice cube, m = 18.6 g

The heat of fusion of ice, ΔHₓ = 333 J/g

The heat energy of a substance is equal to the product of the mass and heat of fusion of that substance. It is given by the equation,

                               <em> Q = m · ΔHₓ     joules</em>

Substituting the given values in the above equation

                                Q = 18.6 g x 333 J/g

                                    = 6193.8 J

Hence, the heat required to melt the ice cube is, Q = 6193.8 J

5 0
3 years ago
What is a “plate” in geological terms
Tju [1.3M]

Answer:a plate is a rigid segment Of The earth's lithosphere that moves horizontally and adjoins other plates along then zone of seismic activity.

Explanation:

A plate is a rigid segment Of The earth's lithosphere that moves horizontally and adjoins other plates along then zone of seismic activity.plates may include portion of both continents and ocean basin.

3 0
3 years ago
Can you give me an example of how sound passes through a solid?please help
nydimaria [60]
When a layer of cold air close to the ground is covered by a layer of warmer air, sound waves traveling upward may be bent, or refracted, by the difference in temperature and redirected toward the ground.
5 0
2 years ago
Read 2 more answers
Find the slope of the line that passes through the points (-1, 3) and (2, -5)-
spayn [35]

Answer:

m=−8/3

Explanation:

6 0
3 years ago
Read 2 more answers
Two circular coils are concentric and lie in the same plane. The inner coil contains 170 turns of wire, has a radius of 0.0095 m
PIT_PIT [208]

Answer:

Current in outer circle will be 15.826 A

Explanation:

We have given number of turns in inner coil N_I=170

Radius of inner circle r_i=0.0095m

Current in the inner circle I_i=8.9A

Number of turns in outer circle N_o=150

Radius of outer circle r_o=0.015m

We have to find the current in outer circle so that net magnetic field will zero

For net magnetic field current must be in opposite direction as in inner circle

We know that magnetic field is given due to circular coil is given  by

B=\frac{N\mu _0I}{2r}

For net magnetic field zero

\frac{N_I\mu _0I_I}{2r_I}=\frac{N_O\mu _0I_0}{2r_O}

So \frac{170\times \mu _0\times 8.9}{2\times 0.0095}=\frac{150\times \mu _0I_O}{2\times 0.015}

I_O=15.92A

4 0
2 years ago
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