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yan [13]
3 years ago
14

10. How many moles of Fe2+ can be oxidized to Fe+ by 0.75 mole of Cl2, according to

Chemistry
1 answer:
Nat2105 [25]3 years ago
4 0
It means 3 moles of Fe2+ are being oxidized to Fe3+.

3Fe2+ → Fe3+ ; so balance that out you get 3Fe2+ → 3Fe3+ + 3e- (1)

Therefore,from the balanced equation you only need 1 mole of Cl2 to oxidize 3moles of Fe2+ .
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Whitepunk [10]
I think B
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3 years ago
Wat are representative elements
AnnyKZ [126]
In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements
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3 years ago
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A percent composition analysis yields
siniylev [52]

Answer:

PCl₃

Explanation:

To determine the empirical formula of a compound, we need to follow a series of steps.

Step 1: Divide each percent composition by the atomic mass of the element

P: 22.6/30.97 = 0.729

Cl: 77.4/35.45 = 2.18

Step 2: Divide all the numbers by the smallest one, i.e. 0.729

P: 0.729/0.729 = 1

Cl: 2.18/0.729 ≈ 3

The empirical formula of the compound is PCl₃.

3 0
3 years ago
What will happen to the pressure when the temperature of a gas increases
Galina-37 [17]
Not guarenteed the answer, but as the temperature increases, the molecules in the gas move faster, impacting the gas's containor more frequently and exerting a greater force, according to Gay-Lussac's Law. I hope this helps you.
5 0
3 years ago
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Be sure to answer all parts. Sulfur dioxide is released in the combustion of coal. Scrubbers use lime slurries of calcium hydrox
scoray [572]

<u>Answer:</u> The balanced chemical equation is written below and \Delta S^o for the reaction is -160.6 J/K

<u>Explanation:</u>

When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.

The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

Ca(OH)_2(s)+SO_2(g)\rightarrow CaSO_3(s)+H_2O(l)

To calculate the entropy change of the reaction, we use the equation:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]

For the given reaction:

\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]

Taking the standard entropy change values:

\Delta S^o_{CaSO_3(s)}=101.4Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O(l)}=69.9Jmol^{-1}K^{-1}\\\Delta S^o_{Ca(OH)_2(s)}=83.4Jmol^{-1}K^{-1}\\\Delta S^o_{SO_2(g)}=248.5Jmol^{-1}K^{-1}

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K

Hence, the balanced chemical equation is written above and \Delta S^o for the reaction is -160.6 J/K

3 0
3 years ago
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