The electron configuration for Boron (B) is given as 
or ![[He] 2s^2 2p^1](https://tex.z-dn.net/?f=%5BHe%5D%202s%5E2%202p%5E1)
Answer:
Boron (B) has an atomic number equal to 5 and is an element from Group 13 of the periodic table. It has a total of 5 electrons of which 3 are valence electrons.
The electron configuration for Boron can be written with the first two electrons in the 1s orbital. Since 1s orbital can hold only two electrons, out of the remaining three electrons; two electrons will go in the 2s orbital. The remaining one electron in the 2p orbital. Therefore the Boron electron configuration will be
Since 
is the electron configuration for Helium, Electron configuration for Boron can also be written as
<em>(Refer attached figure)</em>
The given reaction is exothermic,
X + Y ----> XY + Heat
Heat is a product. So, if the temperature is increased, the equilibrium is shifted towards the reactants. So, the <u>[X] increases</u>.
The cell cycle is important because it helps cells to sustain their lives
Cool dry air meeting warm Moist air
The neutral atom of lead must have 82 protons while ions can have b or less than 82.
The atomic number of an element is the number of protons in the nucleus of the element.
Also, for neutral atoms, the number of protons equals the number of electrons.
In ionic form, the number of protons/electrons of an atom may vary and be different from that of the neutral form.
Positive charges mean that the ion has less proton than its neutral version while negative charges mean that it has more electrons than its neutral version.
Thus, the neutral atom of lead will contain an equal number of protons as the electrons while its ionic form can have more or less than 82 protons.
More on atoms can be found here: brainly.com/question/803445?referrer=searchResults
