The number of liters of 3.00 M lead (II) iodide : 0.277 L
<h3>Further explanation</h3>
Reaction(balanced)
Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)
moles of KI = 1.66
From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):
Here we have to choose the correct statement behind the polarity of the water molecule.
The polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.
The bonding of the water (H₂O) molecule is shown in the figure. There remain two lone pair of electrons on the oxygen atom. The oxygen atom has 6 valence electrons among which 2 are involved to make the covalent bond with two hydrogen atom.
The lone pair if electrons exerted lone pair-bond pair repulsion and H₂O has a bent structure as shown in the figure. In this way the dipole moment generated by oxygen and hydrogen cannot be nullified and it has a permanent dipole moment which leads the molecule to be polar in nature.
The water molecule is not linear in nature it has bent structure.
There is a huge difference of electronegativity between the hydrogen (H) and oxygen (O) atom. The oxygen atom is highly electronegative whereas the hydrogen atom is electropositive in nature.
The hydrogen bond formation is due to the fact the molecule is polar in nature.
S * C = E
S=starting value, C=conversion factor, and E is our end converted result.
S=7598 feet,C= miles, E=1.4390151515152 miles
Answer:7598 ft =1.4390151515152 mi
