Generally, chemists prefer to use morality (B) because it only invovles measuring the final volume of the solution and amount of moles of the solute
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Answer:- 171 g
Solution:- It asks to calculate the grams of sucrose required to make 1 L of 0.5 Molar solution of it.
We know that molarity is moles of solute per liter of solution.
If molarity and volume is given then, moles of solute is molarity times volume in liters.
moles of solute = molarity* liters of solution
moles of solute = 0.5*1 = 0.5 moles
To convert the moles to grams we multiply the moles by molar mass.
Molar mass of sucrose = 12(12) + 22(1) + 11(16)
= 144 + 22 + 176
= 342 grams per mol
grams of sucrose required = moles * molar mass
grams of sucrose required = 0.5*342 = 171 g
So, 171 g of sucrose are required to make 1 L of 0.5 molar solution.
The answer is A (The ability to react with oxygen)
Answer:
Option A is correct. About 5 g of the KClO3 is dissolved
Explanation:
KClO3 is not very good soluble in water.
So, Option C is impossible, because KClO3 is poorly soluble in water.
The low solubility of KClO3 in water causes KClO3 to isolate itself from the reaction mixture by precipitating out of solution.
So, option D will either happen.There will be a part of KClO3 dissolve.
At 10 °C, KClO3 has a solubility of 4.46 g/100 gram (10 °C).
Option A is correct. About 5 g of the KClO3 is dissolved
Base + acid = salt + water
Example :
<span>HCl + NaOH = NaCl + H</span>₂<span>O
</span>
Answer A
hope this helps!
