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OleMash [197]
3 years ago
12

How many molecules are there in 0.45 moles of so3

Chemistry
1 answer:
vivado [14]3 years ago
6 0

Answer:

2.71

Explanation:

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I well give 300 points for this question
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If the temperature of a fish population increases then, the population of fish will increase because the fish like warmer areas to breed and lay eggs.

I'm not sure if this is correct. But always use IF THEN and BECAUSE when writing a hypothesis 
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A laboratory requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solutio
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The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.
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Determine the number of significant figures in each of the following
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A. 3 Significant Figures

B. 6 Significant Figures

C. 2 Significant Figures

D. 4 Significant Figures

E. 4 Significant Figures

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An aqueous solution is made from a molecular compound rather than from an ionic compound. If some ions are present in solution,
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As a result, electrolyte solutions readily conduct electricity. ... By contrast, if a compound dissociates to a small extent, the solution will be a weak conductor of electricity; ... Typically, nonelectrolytes are primarily held together by covalent rather than ionic bonds. ... Explain why some molecules do not dissolve in water.

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A sample of methane gas, CH4, occupies 3.25 L at temperature of 19.0 o C. If the pressure is held constant, what will be the tem
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Answer:

625.46 °C

Explanation:

We'll begin by converting 19 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 19 °C

T(K) = 19 °C + 273

T(K) = 292 K

Next, we shall determine the Final temperature. This can be obtained as follow:

Initial volume (V₁) = 3.25 L

Initial temperature (T₁) = 292 K

Final volume (V₂) = 10 L

Final temperature (T₂) =?

V₁/T₁ = V₂/T₂

3.25 / 292 = 10 / T₂

Cross multiply

3.25 × T₂ = 292 × 10

3.25 × T₂ = 2920

Divide both side by 3.25

T₂ = 2920 / 3.25

T₂ = 898.46 K

Finally, we shall convert 898.46 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 898.46 K

T(°C) = 898.46 – 273

T(°C) = 625.46 °C

Therefore the final temperature of the gas is 625.46 °C

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3 years ago
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