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3 years ago

How many miles of NaCl are in 250 mL of a 0.4 M solution?

Chemistry

1 answer:

creativ13 [48]3 years ago

8 0

Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution.

Explanation:

First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.

250 ml . 1L/1000 L . 0.4mol / 1L

Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.

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In which chemical system is molecule to ion attractions present? A) KNO3(s) B) KNO3(l) C) KNO3(aq) D) KNO3(g)

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Answer:

$KNO_3 (aq)$

Explanation:

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Nitrate, our anion, attracts the partially positive ends of water molecules by attracting them via hydrogen atom.

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3 years ago

Use the following graph of a car traveling on a straight northerly path to answer this question. At what time would the

BARSIC [14]

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4 years ago

how much heat, in terms in q, would it take to produce the change in temperature indicated in the picture? what is your reasonin

STALIN [3.7K]

Answer:

1. q.

2. 2q.

3. 3q.

4. 6q.

Explanation:

We'll begin by calculating the specific heat capacity of the liquid. This can be obtained as follow:

Mass (m) = 25 g

Change in temperature (ΔT) = 20 °C

Heat (Q) = q

Specific heat capacity (C) =?

Q = MCΔT

q = 25 × C × 20

q = 500C

Divide both side by 500

C = q/500

C = 2×10¯³ qg°C

Therefore, the specific heat capacity of liquid is 2×10¯³ qg°C

Now, we shall determine the heat required to produce the various change in temperature as follow:

2. Mass (m) = 50 g

Change in temperature (ΔT) = 20 °C

Specific heat capacity (C) = 2×10¯³ qg°C

Heat (Q) =?

Q = MCΔT

Q = 50 × 2×10¯³ × 20

Q = 2q.

Therefore, the heat required is 2q.

3. Mass (m) = 25 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) = 2×10¯³ qg°C

Heat (Q) =?

Q = MCΔT

Q = 25 × 2×10¯³ × 60

Q = 3q.

Therefore, the heat required is 3q.

4. Mass (m) = 50 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) = 2×10¯³ qg°C

Heat (Q) =?

Q = MCΔT

Q = 50 × 2×10¯³ × 60

Q = 6q.

Therefore, the heat required is 6q.

4 0

3 years ago

How many calories is required to change the temperature of 2.18g of water from 15.3°C to 69.5°C. The specific heat of liquid wat

lozanna [386]

The number of calories that are required to change the temperature of 2.18 g of water from 15.3 c to 69.5 c is 118.16 cal

calculation

Heat in calories = MCΔ T where,

M(mass)= 2.18 g
C(specific heat capacity)= 1.00 cal/g/c
ΔT( change in temperature)= 69.5- 15.3 =54.2 c

heat is therefore= 2.18 g x 1.00 cal/g/c x 54.2 c=118.16 cal

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3 years ago

Read 2 more answers

so how many moles of Fe are in 3.10 mole of iron oxide FeO still waiting for answer please, my grandchild needs help that I can'

alisha [4.7K]

The answer is 3.10 because it's still the same amount moles of iron.

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3 years ago

How many miles of NaCl are in 250 mL of a 0.4 M solution?​

How many miles of NaCl are in 250 mL of a 0.4 M solution?