Answer:
1. 25 moles water.
2. 41.2 grams of sodium hydroxide.
3. 0.25 grams of sugar.
4. 340.6 grams of ammonia.
5. 4.5x10²³ molecules of sulfur dioxide.
Explanation:
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In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:
1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:
2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:
3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:
4. Here, since the molar mass of ammonia is 17.03 g/mol:
5. Here, since the molar mass of SO2 is 64.06 g/mol:
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Answer:
C. Graph C
Explanation:
We have a mixture of water and ice.
At 0 °C they are at equilibrium.
water-to-ice rate = ice-to-water rate
Next, we lower the temperature to -3 °C — just slightly below freezing.
The water will slowly turn to ice.
The water-to-ice rate will be slightly faster than the ice-to-water rate.
The purple bar will be slightly higher than the blue bar.
Graph C best represents the relative rates
A. is wrong. The ice-to-water rate is faster, so the water is melting. The temperature is slightly above freezing (say, 3 °C).
B. is wrong. The two rates are equal, so the temperature is 0 °C.
D. is wrong. The water-to-ice rate (freezing) is much greater than the ice-to-water rate, so the temperature is well below freezing( say, -10 °C).
Answer:
Reaction with water: Aluminum oxide is insoluble in water and does not react like sodium oxide and magnesium oxide.
Explanation:
Relation between molarity and molar mass is as follows.
Molarity = 
It is given that mass is 1 mg/ml which is also equal to 
g.
Molecular mass = 58 Da = 58 g/mol
Volume = 1 ml
Therefore, calculate molarity as follows.
Molarity =
= 
= 0.0172 molar
It is known that 1 molar equals 1000 millimolar.
So, 0.0172 molar = 
= 17.2 millimolar
Thus, we can conclude that the concentration of given solution is 17.2 millimolar.
