Answer:
0.083 M
Explanation:
We'll begin by calculating the number of mole in 0.43 g of KHP (potassium hydrogen phthalate, C₈H₅O₄K). This is can be obtained as follow:
Mass of C₈H₅O₄K = 0.43 g
Molar mass of C₈H₅O₄K = (8×12) + (5×1) + (16× 4) + 39
= 96 + 5 + 64 + 39 = 204 g/mol
Mole of C₈H₅O₄K =?
Mole = mass / molar mass
Mole of C₈H₅O₄K = 0.43 / 204
Mole of C₈H₅O₄K = 0.002 mole
Next, we shall determine the number of mole of NaOH required to react with 0.43 g (i.e 0.002 mole) of KHP. This can be obtained as follow:
C₈H₅O₄K + NaOH → C₈H₄O₄KNa + H₂O
From the balanced equation above,
1 mole of KHP reacted with 1 mole of NaOH.
Therefore, 0.002 mole of KHP will also react with 0.002 mole of NaOH.
Next, we shall convert 24.11 cm³ to L. This can be obtained as follow:
1000 cm³ = 1 L
Therefore,
24.11 cm³ = 24.11 cm³ × 1 L / 1000 cm³
24.11 cm³ = 0.02411 L
Finally, we shall determine the molarity of NaOH. This can be obtained as follow:
Mole of NaOH = 0.00 2 mole
Volume = 0.02411 L
Molarity of NaOH =?
Molarity = mole /Volume
Molarity of NaOH = 0.002 / 0.02411
Molarity of NaOH = 0.083 M
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