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2 years ago

Heelllllppppppppp me please in neeeeed

Mathematics

1 answer:

mestny [16]2 years ago

3 0

1 is b, 2 is d, 3 is e, 4 is c, 5 is a

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Factor the following expression <br> 10x^5+5x^3-14x^2-7-

Tatiana [17]

Answer:

C. (5x^3-7)(2x^2+1)

Step-by-step explanation:

Given expression is,

10x^5+5x^3-14x^2-7

=10x^5-14x^2 + 5x^3 - 7 (By the commutative property)

=2x^2(5x^3-7)+5x^3-7 (Taking 2x^3 common from first two terms )

=(5x^3-7)(2x^2+1) (Taking 5x^3-7 common from both terms)

\implies 10x^5+5x^3-14x^2-7=(5x^3-7)(2x^2+1)

Hence, Option C is correct

5 0

2 years ago

Explain why f(x) =√2+x - √2/x, is not continuous at x = 0.<br> Picture provided below.

IrinaK [193]

Answer: A

Step-by-step explanation:

If you put 0 in for x, then you would be dividing by 0. Dividing by 0 is always undefined.

3 0

3 years ago

Read 2 more answers

8% of what number is 2 :)

Alisiya [41]

8% of what number is 2 - 268832

8 0

2 years ago

Read 2 more answers

A school is selling tickets to a drama performance. On the first day of ticket sales the school sold 3 adult tickets and 1 child

baherus [9]

Answer:

System of linear equations

$\left\{\begin{matrix} 3a+c=38 \\\\ 3a+2c=52 \end{matrix}\right.$

a: adult ticket price and c: child ticket price

Step-by-step explanation:

This system of equations can be used to find the price of the adult and child tickets.

We have two equations (one for each day) and two unknowns (adult ticket price and child ticket price).

Let a: adult ticket price and c: child ticket price,

we have for the first day that 3 adult tickets and 1 child ticket adds $38:

$3a+1c=38$

and for the second day we have that 2 adult tickets and 2 child tickets adds $52:

$3a+2c=52$

If we write this as a system of equations, we have:

$\left\{\begin{matrix} 3a+c=38 \\\\ 3a+2c=52 \end{matrix}\right.$

4 0

2 years ago

PLEASE HELP ASAP!! ONLY IF YOU KNOW THE ANSWER! THANK YOU SO MUCH!

telo118 [61]

Answer:

f(x)=-x

I hope this helps :)

8 0

2 years ago