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masha68 [24]
3 years ago
9

Solve the following system 6x-3y=15 x+3y=-8

Mathematics
2 answers:
MArishka [77]3 years ago
8 0

Answer:

(1,-3)

Step-by-step explanation:

6x-3y=15

<em>substitute x with 1 and y with -3</em>

6(1)-3(-3)=15

6+9=15 so that's true

x+3y=-8

<em>again substitute x with 1 and y with -3</em>

(1)+3(-3)= -8

1-9=-8

-8=-8 and that's true

hope i helped

pentagon [3]3 years ago
7 0
<h2>Answer:</h2>

This system can be solved for x by elimination.

6x - 3y = 15\\  x + 3y = -8\\\\7x = 7\\\\x = 1

Now, with what we found for x, we plug it back into one of the equations to solve for y. I chose the second one.

1 + 3y = -8\\\\3y = -9\\\\y = -3

Now, we have our solution.

(1, -3)

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Answer:

To make a profit of at least $500 she must sell at least 12 necklaces

Step-by-step explanation:

Joyce rented a booth at a carnival at a cost of $95 to sell handmade beaded necklaces. The cost of making and packaging each beaded necklace was $15. If Joyce sells the beaded necklaces at $35 each then we have to find beaded necklaces she sell to make a profit of at least $500.

The costs side of the equation, we have:

Let no. of necklaces that she sell are x

∴ The cost of making and packaging x beaded necklace is $15x

Total Cost = 95+15x

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To make a profit of at least $500 the equation can be written as

95+15x+500\leq35x

595\leq50x

⇒ x\geq11.9=12

Hence,  to make a profit of at least $500 she must sell at least 12 necklaces



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