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3 years ago

8th grade math please help.

Mathematics

1 answer:

GuDViN [60]3 years ago

3 0

Answer:

angle 8 and angle 4

Step-by-step explanation:

angle 4 is the correct answer because it is the same as 8 but on the other side

You might be interested in

1 name a pair of complementary angles

liraira [26]

Complementary angles add to 90 degrees.
So your answer is B. Angles 1 and 2

4 0

2 years ago

Orlando is mixing nuts and cereal squares to make a party mix. Nuts sell 7$ a pound and cereal squares sell for 4$ a pound. If O

Kamila [148]

Answer:

25 pounds of nuts and 5 pounds of cereal squares.

Step-by-step explanation:

Let amount of nuts be x and cereals squares be y pounds.

x + y = 30

7x + 4y = 30*6.5

7x + 4y = 195 Multiply the first equation by -4:

-4x - 4y = -120 Adding:

3x = 75

x = 25 pounds.

y = 30 - 25 = 5 pounds.

4 0

2 years ago

20. Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal

lesya [120]

Given:

Initial point = (–5, 3)

Terminal point = (1, –6)

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1.

Solution:

The interval is 0 ≤ t ≤ 1, initial point is (–5, 3) and terminal point is (1, –6). It means,

$x(0)=-5,y(0)=3$

$x(1)=1,y(1)=-6$

Put t=1 in each parametric equation.

In option A,

$x(1)=-5+1=-4\neq 1$

In option B,

$x(1)=-5+3(1)=-5+3=-2\neq 1$

In option D,

$x(1)=-5+8(1)=-5+8=3\neq 1$

Therefore, options A, B and D are incorrect.

In option C,

$x(1)=-5+6(1)=-5+6=1$

$y(1)=3-9(1)=3-9=-6$

Put t=0 in x(t) and y(t).

$x(0)=-5+6(0)=-5$

$y(0)=3-9(0)=3$

Since, only in option C $x(0)=-5,y(0)=3,x(1)=1,y(1)=-6$ , therefore, the correct option is C.

7 0

2 years ago

Factorise <img src="https://tex.z-dn.net/?f=2t%5E2%2B5t%2B2" id="TexFormula1" title="2t^2+5t+2" alt="2t^2+5t+2" align="absmiddle

blondinia [14]

Answer: $\displaystyle\ \large \boldsymbol{ 2t^2+5t+2= {(2t+1) (t+2)}}$

Step-by-step explanation:

$\displaystyle\ \large \boldsymbol{} 2t^2+5t+2=0 \\\\2t^2+\underbrace{4t+t}_{5t}+2=0 \\\\ (2t^2+4t)+(t+2)=0 \\\\ 2t(\underline{t+2})+(\underline{t+2})=0 \\\\ \boxed{(2t+1) (t+2)=0 }$

3 0

2 years ago

William is digging a hole to plant a tree.The hole has to be in 2 ft deep.He is able to dig at a rate of 1/2 ft. per minute.Writ

Mars2501 [29]

Answer:

$y=-\dfrac{1}{2}x+2$

Step-by-step explanation:

Let

x = the amount of time William has been digging

y = the amount he has left to dig

The hole has to be in 2 ft deep. This means when William starts, the hole was 0 feet deep and has left 2 ft to dig. Hence, y-intercept is $b=2$

He is able to dig at a rate of $\frac{1}{2}$ ft per minute. Thus, the slope is $m=-\frac{1}{2}$ (negative because the depth left to dig is decreasing).

The slope-intercept form of the equation is $y=mx+b,$ so in your case this equation is

$y=-\dfrac{1}{2}x+2$

8 0

2 years ago