Gosh, I love chem!
[H2O]/t should be 0.085M/s
this is because of the coefficients in front of H2S and H2O being the same.
the significance of this answer is that the H2S disappears at the same rate H2O appears.
Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>
Answer:
1250joules
Explanation:
The kinetic energy is energy in motion and it's formula is
KE =1/2MV^2
M represent mass which is 100Kg.
V represent velocity which is 5m/s
Therefore, KE = 1/2×100×5× 5
= 50 × 25
KE= 1250joules
Answer:
there are no options but i would say Alaska
Explanation:
