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2 years ago

Identify the reactants in the equation: 6C0, + 6H2O - CHUO+ 60,

Chemistry

1 answer:

Effectus [21]2 years ago

5 0

Answer:

The correct answer is d. 6H20 + 6CO2.

The reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.

Explanation:

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PLEASE! I need help in chemistry. If you are good in chemistry, please send your gm^ail. I have a lab to send. But I am stuck. P

stiv31 [10]

Answer:

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6 0

2 years ago

Choose the covalent compounds from the following choices Br2 MgS SO2 KF

Novosadov [1.4K]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent Bond

Between 0.4 and 1.7 then it is Polar Covalent Bond

Greater than 1.7 then it is Ionic

For Br₂;

E.N of Bromine = 2.96

________

E.N Difference 0.00 (Non Polar Covalent Bond)

For MgS;

E.N of Sulfur = 2.58

E.N of Magnesium = 1.31

________

E.N Difference 1.27 (Ionic Bond)

For SO₂;

E.N of Oxygen = 3.44

E.N of Sulfur = 2.58

________

E.N Difference 0.86 (Polar Covalent Bond)

For KF;

E.N of Fluorine = 3.98

E.N of Potassium = 0.82

________

E.N Difference 3.16 (Ionic Bond)

Result: The Bonds in Br₂ and SO₂ are Covalent in Nature.

3 0

3 years ago

Can you treat a sulfuric acid burn with sodium hydroxide

Alina [70]

Answer:

I think yes

Explanation:

sorry i havent done these type a questions in a while

3 0

2 years ago

20.0 g of bromic acid, HBrO3, is reacted with excess HBr.

Blababa [14]

After Rounding off The percentage yield is 64%

<h3>What is Percentage Yield ?</h3>

It is the ratio of actual yield to theoretical yield multiplied by 100% .

It is given in the question

20.0 g of bromic acid, HBrO3, is reacted with excess HBr.

The reaction is

HBrO₃ (aq) + 5 HBr (aq) → 3 H₂O (l) + 3 Br₂ (aq)

Actual yield = 47.3 grams

Molecular weight of Bromic Acid is 128.91 gram

Moles of Bromic Acid = 20/128.91 = 0.155 mole

Mole fraction ratio of Bromic Acid to Bromine is 1 :3

Therefore for 0.155 mole of Bromic Acid 3 * 0.155 = 0.465 mole of Bromine is produced.

1 mole of Bromine = 159.8 grams of Bromine

0.465 of Bromine = 74.31 grams of Bromine

Percentage Yield = (47.3/74.31)*100 = 63.65 %

After Rounding off The percentage yield is 64% .

To know more about Percentage Yield

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1 year ago

Nitrogen fixing bacteria in soil turns nitrogen gas into

Alika [10]

<span>Nitrogen gas is converted to nitrate compounds by nitrogen-fixing bacteria in soil turns nitrogen gas into root nodules. Nitrogen is the most commonly limiting nutrient in plants. Legumes use nitrogen fixing bacteria, specifically symbiotic rhizobia bacteria, within their root nodules to counter the limitation.</span>

4 0

2 years ago