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Lapatulllka [165]
2 years ago
5

Un objeto de 0.5kg de masa se desplaza a lo largo de una trayectoria rectilínea con aceleración constante de 0.3m/s2. Si partió

del reposo y la magnitud de su cantidad de movimiento en kg*m/s después de 8s es:
Physics
1 answer:
den301095 [7]2 years ago
6 0

Answer:

p = 1.2 kg-m/s

Explanation:

The question is, "An object of mass 0.5kg is moving along a rectilinear path with constant acceleration of 0.3m / s2. If it started from rest and the magnitude of its momentum in kg * m / s after 8s is".

Mass of the object, m = 0.5 kg

Acceleration of the object, a = 0.3 m/s²

We need to find the momentum after 8 seconds.

We know that,

p=F\times t

i.e.

p = mat

So,

p=0.5\times 0.3\times 8\\\\p=1.2\ kg-m/s

So, the momentum of the object is 1.2 kg-m/s.

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Resistance = (10 V) / (5 A)

Resistance = 2 ohms.

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Do 10 grams of oxygen atoms and 10 grams of iron atoms contain the same number of particles
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A 975-kg sports car (including driver) crosses the rounded top of a hill at determine (a) the normal force exerted by the road o
iVinArrow [24]
There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill: v=15 m/s
- radius of the hill: r=100 m

Solution:

(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car W=mg (downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force, m \frac{v^2}{r}, so we can write:
mg-N=m \frac{v^2}{r} (1)
By rearranging the equation and substituting the numbers, we find N:
N=mg-m \frac{v^2}{r}=(975 kg)(9.81 m/s^2)-(975 kg) \frac{(15 m/s)^2}{100 m}=7371 N

(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:
N=mg-m \frac{v^2}{r}=(62 kg)(9.81 m/s^2)-(62 kg) \frac{(15 m/s)^2}{100 m}=469 N

(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:
mg=m \frac{v^2}{r}
from which we find
v= \sqrt{gr}= \sqrt{(9.81 m/s^2)(100 m)}=31.3 m/s
7 0
3 years ago
Which of the following is transferred to an object when work is done? A. motion B. energy C. force D. friction
ziro4ka [17]
The answer will be letter B because after work people need some energy
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3 years ago
What is the volume of an object if it has a mass of 10 grams and a density of 87 g/ml
belka [17]

Answer:

<h3>The answer is 0.115 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 10 g

density = 87 g/ml

We have

volume =  \frac{10}{87}  \\  = 0.114942528...

We have the final answer as

<h3>0.115 mL</h3>

Hope this helps you

5 0
3 years ago
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