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Answer:
3°C
Explanation:
We can that heat Q=m
dT
Where m is the mass
= specific heat capacity
dT = Temperature difference
here we have given m=625 g =.625 kg
specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)
=25°C
we have to find
we have also given Q=10.9 KJ
10.9=0.625×0.79×(25-
)
25-
=22
=3°C
Complete Question:
When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.
Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?
Answer:
ΔE = 1.224 * 10⁻²² J
Explanation:
In the 6f state, the orbital quantum number, L = 3
The magnetic quantum number, ![m_{L} = -3, -2, -1, 0, 1, 2, 3](https://tex.z-dn.net/?f=m_%7BL%7D%20%3D%20-3%2C%20-2%2C%20-1%2C%200%2C%201%2C%202%2C%203)
The change in energy due to Zeeman effect is given by:
![\triangle E = m_{L} \mu_{B} B](https://tex.z-dn.net/?f=%5Ctriangle%20E%20%3D%20m_%7BL%7D%20%5Cmu_%7BB%7D%20B)
Magnetic field B = 2.02 T
Bohr magnetron, ![\mu_{B} = 9.274 * 10^{-24} J/T](https://tex.z-dn.net/?f=%5Cmu_%7BB%7D%20%3D%209.274%20%2A%2010%5E%7B-24%7D%20J%2FT)
![\triangle E = 6 * 9.274 * 10^{-24} * 2.2\\](https://tex.z-dn.net/?f=%5Ctriangle%20E%20%3D%206%20%2A%209.274%20%2A%2010%5E%7B-24%7D%20%2A%202.2%5C%5C)
ΔE = 1.224 * 10⁻²² J
Answer:
130 km at 35.38 degrees north of east
Explanation:
Suppose the HQ is at the origin (x = 0, y = 0)
So the coordinates of the helicopter after the 1st flight is
![x_1 = -120cos70^o = -41.04 km](https://tex.z-dn.net/?f=x_1%20%3D%20-120cos70%5Eo%20%3D%20-41.04%20km)
![y_1 = -120sin70^o = -112.763 km](https://tex.z-dn.net/?f=y_1%20%3D%20-120sin70%5Eo%20%3D%20-112.763%20km)
After the 2nd flight its coordinate would be:
![x_2 = x_1 - 75sin60^o = -41.04 - 64.95 = -106km](https://tex.z-dn.net/?f=x_2%20%3D%20x_1%20-%2075sin60%5Eo%20%3D%20-41.04%20-%2064.95%20%3D%20-106km)
![y_2 = y_1 + 75cos60^o = -112.763 + 37.5 = -75.263 km](https://tex.z-dn.net/?f=y_2%20%3D%20y_1%20%2B%2075cos60%5Eo%20%3D%20-112.763%20%2B%2037.5%20%3D%20-75.263%20km)
So in order to fly back to its HQ it must fly a distance and direction of
north of east
A soccer ball would keep moving forever without physics, because without force to act upon the soccer ball, it could, or will not be able to stop the acceleration. And force is a factor in physics.