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yulyashka [42]
2 years ago
8

A germanium piece is heated, then its resistance increases or decreases​

Physics
1 answer:
LekaFEV [45]2 years ago
8 0

Answer:

decreases

Explanation:

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The momentum of a falling rock is found to be 200 kg m/s. What is the mass of the rock if it falls with a velocity of 5.0 m/s
Snezhnost [94]

Answer:

\boxed {\boxed {\sf 40 \ kilograms}}

Explanation:

Momentum is the product of velocity and mass. The formula is:

p=m*v

We know the rock is falling. Its momentum is 200 kilograms meters per second and its velocity is 5 meters per second. Substitute the values into the formula.

200 \ kg \ m/s = m * 5.0 \ m/s

We are solving for m, the mass. We must isolate the variable. It is being multiplied by 5 meters per second. The inverse of multiplication is division, so we divided both sides by 5.0 m/s.

\frac{200 \ kg \ m/s}{5.0 \ m/s}=\frac{ m* 5.0 \ m/s }{5.0 \ m/s}

\frac{200 \ kg \ m/s}{5.0 \ m/s}=m

The units of meters per second (m/s) cancel.

\frac{200 \ kg}{5.0 } =m

40 \ kg = m

The falling rock has a mass of <u>40 kilograms.</u>

4 0
3 years ago
4.
Pie

Answer:

b

Explanation:

it compresses hot air turning into cool air almost like a reverse tornado

3 0
3 years ago
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Suppose that a uniform electric field exists in a certain region of space. Now consider a mathematical plane surface of area A.
____ [38]

Answer: The normal of the plane must be parallel to the electric field vector.

Explanation:

the normal to the surface is defined as a versor that is perpendicular to the plane.

Now, if the angle between this normal and the line of the field is θ, we have that the flux can be written as:

Φ = E*A*cos(θ)

Where E is the field, A is the area and θ is the angle already defined.

Now, this maximizes when θ = 0.

This means that the normal of the surface must be parallel to the electric field

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Psy 325 has anyone had this course
Pavlova-9 [17]
I do not have that one but i think you can download that in the internet.
6 0
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<span>A differences in the warmth, or moisture level as well as neighbouring areas of pressure in </span>air cause air<span> to circulate. in the earth's atmosphere.</span>
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