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sleet_krkn [62]
3 years ago
11

What is the resistance of a circuit with a voltage of 10 V and current of 5A is?

Physics
2 answers:
shtirl [24]3 years ago
8 0

Answer:

2 ohms.

Explanation:

Calculating the resistance of a circuit is very simple, you just have to divide the voltage value by the current value. With this calculation you will have the resistance value of the circuit.

R = (Voltage) / (current)

R= (10) / (5)

R= 2 ohms

wolverine [178]3 years ago
5 0

Resistance = (voltage) / (Current)

Resistance = (10 V) / (5 A)

Resistance = 2 ohms.

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DaniilM [7]
I think it is A) fault
3 0
2 years ago
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A diffraction grating is placed 1.00 m from a viewing screen. Light from a hydrogen lamp goes through the grating. A hydrogen sp
Colt1911 [192]

Answer:

λ = 396.7 nm

Explanation:

For this exercise we use the diffraction ratio of a grating

           d sin θ = m λ

in general the networks works in the first order m = 1

we can use trigonometry, remembering that in diffraction experiments the angles are small

           tan θ = y / L

           tan θ = \frac{sin \theta}{cos \theta} = sin θ

           sin θ = y / L

we substitute

          d \  \frac{y}{L} = m λ

with the initial data we look for the distance between the lines

           d = \frac{m \lambda \ L}{y}

           d = 1 656 10⁻⁹ 1.00 / 0.600

            d = 1.09 10⁻⁶ m

for the unknown lamp we look for the wavelength

           λ = d y / L m

           λ = 1.09 10⁻⁶ 0.364 / 1.00 1

           λ = 3.9676 10⁻⁷ m

           λ = 3.967 10⁻⁷ m

         

we reduce nm

           λ = 396.7 nm

8 0
2 years ago
A single-turn square loop carries a current of 16 A . The loop is 15 cm on a side and has a mass of 3.8×10^−2kg . Initially the
DiKsa [7]

Answer:

The minimum magnetic field is 0.078 T.

Explanation:

Given that,

Current = 16 A

Side = 15 cm

Mass m= 3.8\times10^{-2}\ kg

Mass each segment in given square loop is

m=\dfrac{3.8\times10^{-2}}{4}

We need to calculate the torque due to gravity

Using formula of torque

\tau_{g}=2mg(\dfrac{L}{2})+mgL

\tau_{g}=2mgL

The torque due to magnetic field

\tau_{B}=FL

\tau_{B}=BIL^2

The equilibrium condition

\tau_{B}=\tau_{g}

Put the value into the formula

BIL^2=2mgL

B=\dfrac{2mgL}{IL^2}

B=\dfrac{2mg}{IL}

Put the value into the formula

B=\dfrac{2\times\dfrac{3.8\times10^{-2}}{4}\times9.8}{16\times15\times10^{-2}}

B=0.078\ T

Hence, The minimum magnetic field is 0.078 T.

7 0
3 years ago
A spring with a spring constant of 110n/m is stretched by 12 cm in the positive direction. How much force is applied to the spri
taurus [48]

The force applied on the spring to stretch it is 13.2 N.

Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object. When the load is removed under these conditions, the object returns to its original shape and size.

According to Hooke's law, F = k*e

where F is the force on the spring

k is force constant

and e is extension

F = (110)*(0.12)

F = 13.2 N

For more information on Hooke's law, visit :

brainly.com/question/13348278

#SPJ4

7 0
1 year ago
COULD SOMEONE PLS DO THESE FOR ME <br> I’LL LOVE U FOREVER AND EVER
sladkih [1.3K]
I can help you do them for yourself :)
7 0
3 years ago
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