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koban [17]
3 years ago
8

PLEAEE HELP!!!! Please answer by writing out the correct option!!

Mathematics
2 answers:
insens350 [35]3 years ago
7 0

Answer:

A. B. D.

Step-by-step explanation:

Arlecino [84]3 years ago
3 0

Answer:

a+c+d=180

Step-by-step explanation:

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What is 4x - 1 = 4x + 7
Leokris [45]
This exercise is false, can't be done.
8 0
3 years ago
What is 1/2 +1/10<br> And what is (8x4)- (7x3)
Brut [27]

Answer: 1/2+1/10=3/5

(8x4)-(7x3)= 11

Step-by-step explanation:

8 0
3 years ago
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in a cirlce of radius 5 cm, what is the length in cm of an arc subtended by a central angle measuring 2 radians?
iragen [17]

Answer:

The length L is 10 cm

Step-by-step explanation:

We need to find the length of the arc subtended by a central angle of 2 radians and the circle has radius of 5cm.

So, the formula used will be:

l = r  Θ

Where L= length of arc

r= radius of circle

and  Θ is angle

In The given question

L=?

r = 5 cm

Θ = 2 radians

Putting values in formula:

L = r  Θ

L = 5 * 2

L = 10 cm

So, the length L is 10 cm

4 0
3 years ago
Which of the following is equivalent to log408 rounded to three decimal places?
il63 [147K]

The answer is: 0.564

The explanation is shown below:

1. To solve this problem you must apply the following proccedure:

2. You have the logarithm expression:

log40(8)=x

3. First, you must apply the following property:

a^{loga(x)} =x

4. Therefore, you have:

40^{log40(8)}=40^{x} \\ 8=40^{x}

5. By applying logarithm on both sides, you have:

log(8)=log(40^{x} )

6. By applying the property log(a)^{b} =blog(a):

log(8)=xlog(40)

7. Solve for x:

x=log(8)/log(40)\\ x=0.564

4 0
3 years ago
Limit of f(t) as t approaches 0. f(t) = (t sin(t)) ÷ (1-cos(t))
Hitman42 [59]

Recall the Pythagorean identity,

1-\cos^2t=\sin^2t

To get this expression in the fraction, multiply the numerator and denominator by 1+\cos t:

\dfrac{t\sin t}{1-\cos t}\cdot\dfrac{1+\cos t}{1+\cos t}=\dfrac{t\sin t(1+\cos t)}{\sin^2t}=\dfrac{t(1+\cos t)}{\sin t}

Now,

\displaystyle\lim_{t\to0}\frac{t\sin t}{1-\cos t}=\lim_{t\to0}\frac t{\sin t}\cdot\lim_{t\to0}(1+\cos t)

The first limit is well-known and equal to 1, leaving us with

\displaystyle\lim_{t\to0}(1+\cos t)=1+\cos0=\boxed{2}

4 0
3 years ago
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