A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b
1 answer:
Answer : The molar mass of the solute will be 87.90 g/mol.
Explanation : We know the formula for elevation in boiling point, which is
Δt = i
m
given that, Δt = 0.357, = 5.02 and mass of 
= 40,
on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X
.
Now, 0.250/ 2.844 X = 87.90 g/mol. which is the weight of unknown component.
Explanation : We know the formula for elevation in boiling point, which is
Δt = i
given that, Δt = 0.357,
on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X
Now, 0.250/ 2.844 X
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Answer:
.
Explanation:
Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be and
. The
and
would come from the hydrocarbon, while the
atoms would come from oxygen.
Look up the relative atomic mass of these three elements on a modern periodic table:
:
.
:
.
:
.
Calculate the molar mass of and
:
.
Calculate the number of moles of molecules in
of
:
.
Similarly, calculate the number of moles of molecules in
of
:
.
Note that there is one carbon atom in every molecule. Approximately
of
molecules would correspond to the same number of
atoms. That is:
.
On the other hand, there are two hydrogen atoms in every molecule. approximately
of
molecules would correspond to twice as many
atoms. That is:
.
The ratio between the two is: .
The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be .
If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as
v=1.414 times
<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>Generally, the equation for the volume is mathematically given as
v = sqt(TL/m)
Where
density = mass/length
Therefore
In conclusion,v ratio will give us
v=1.414 times
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