A football field is 0.001 km in length. Since the 1 is in the thousands place, you’d have to run back and forth (0.001 km) 1000 times.
0.001 x 1000 = 1
Answer:
The answer to your question is 0.415 M
Explanation:
Data
volume of H₂SO₄ = 15 ml
[H₂SO₄] = 0.275
volume of NaOH = 20 ml
[NaOH] = ?
Process
1.- Write the balanced chemical reaction
H₂SO₄ + 2NaOH ⇒ Na₂SO₄ + 2H₂O
2.- Calculate the molar mass of H₂SO₄ and the molar mass of NaOH
molar mass of H₂SO₄ = 2 + 32 + (16 x 4) = 98g
molar mass of NaOH = 23 + 16 + 1 = 40 g
3.- Calculate the moles of H₂SO₄ in 15 ml
moles = Molarity x volume
moles = 0.275 x 0.015
moles = 0.0041
4.- Use proportions to calculate the moles of NaOH
1 mol of H₂SO₄ ----------------- 2 moles of NaOH
0.0041 moles ----------------- x
x = (0.0041 x 2) / 1
x = 0.0083 moles of NaOH
5.- Calculate the molarity of NaOH
Molarity = moles/volume
Molarity = 0.0083/0.02
Molarity = 0.415
answer:
I think nine
explanation:
Nuclear fission : It is defined as the splitting of bigger nuclei into two smaller nuclei. During this process neutrons and some energy also released.
Answer:
0.0658 M
Explanation:
The reaction that takes place is:
Na₂SO₄(aq) + BaCl₂(aq) ↔ BaSO₄(s) + 2NaCl(aq)
First we <u>calculate the number of Na₂SO₄ moles</u>:
- 0.4000 g sample * 96.4/100 = 0.3856 g Na₂SO₄
- 0.3856 g Na₂SO₄ ÷ 142.04 g/mol = 2.715x10⁻³ mol Na₂SO₄
Now we <u>convert to moles of BaCl₂</u>:
- 2.715x10⁻³ mol Na₂SO₄ * 1 molBaCl₂/1 molNa₂SO₄ = 2.715x10⁻³ mol BaCl₂
Finally we divide by the volume to <u>calculate the molarity</u>:
- 41.25 mL ⇒ 41.25 / 1000 = 0.04125 L
- 2.715x10⁻³ mol BaCl₂ / 0.04125 L = 0.0658 M
Answer is: mass of iron(II) sulfate pentahydrate (FeSO₄ · 5H₂O) would be 79,62 g.
m(FeSO₄) = 50,0 g.
m(FeSO₄ · 5H₂O) = ?
m(FeSO₄) : M(FeSO₄) = m(FeSO₄ · 5H₂O) : M(FeSO₄ · 5H₂O).
50 g : 151,9 g/mol = m(FeSO₄ · 5H₂O) : 241,9 g/mol.
m(FeSO₄ · 5H₂O) = 50 g · 241,9 g/mol ÷ 151,9 g/mol.
m(FeSO₄ · 5H₂O) = 79,62 g.
M - molar mass.
