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Answer:
To prepare 1.00 L of 2.0 M urea solution, we need to dissolve 120 g of urea in enough water to produce a total of 1.00 L solution
Explanation:
Molarity of a solute in a solution denotes number of moles of solute dissolved in 1 L of solution.
So, moles of urea in 1.00 L of a 2.0 M urea solution = 2 moles
We know, number of moles of a compound is the ratio of mass to molar mass of that compound.
So, mass of 2 moles of urea =
Therefore to prepare 1.00 L of 2.0 M urea solution, we need to dissolve 120 g of urea in enough water to produce a total of 1.00 L solution
So, option (C) is correct.
Answer:
Explanation:
Chemical compounds are substances that contain two or more elements that are chemically bonded together.
Here are 50 chemical compounds:
- Hydrogen peroxide
- Fructose
- Sulfur hexafluoride
- Glucose
- Sulfuric acid
- Calcium nitrate
- Nitrous oxide
- Calcium sulfate
- Ammonia
- Hydrochloric acid
- Potassium nitrate
- Potassium nitrite
- Sucrose
- Methane
- Carbon dioxide
- Dihydrogen oxide
- Putrescine
- Chloroform
- Ethene
- Hydrazine
- Sodium bicarbonate
- Sodium chloride
- Acetate
- Magnesium sulfate
- Urethane
- Butyne
- Nicotine
- Maltose
- Propene
- Tartaric acid
- Nitrogen dioxide
- Butane
- Butene
- Propane
- Pentane
- Hexane
- Benzene
- Isobutane
- Ovalene
- Coronene
- Pyrene
- Chrysene
- Napthalene
- Acetic acid
- Barium iodide
- Aluminium oxide
- Aluminium fluoride
- Styrene
- Toluene
- Vinyl chloride